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2. A titration was done with H2SO4 as the analyte in the flask and Al(OH)3 as the titrant in the burette according to this equation: 3 H2SO4(aq) + 2 Al(OH)3(aq) Al2(SO4)3(5) + 6 H2O) ---> If 47.31 mL of 0.09847 M AI(OH)3 was used to neutralize 25.00 mL of H2SO4, what is the molarity of the H2SO4?

2. A titration was done with H2SO4 as the analyte in the flask and Al(OH)3 as the titrant in the burette according to this equation: 3 H2SO4(aq) + 2 Al(OH)3(aq) Al2(SO4)3(5) + 6 H2O) ---> If 47.31 mL of 0.09847 M AI(OH)3 was used to neutralize 25.00 mL of H2SO4, what is the molarity of the H2SO4?

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter4: Stoichiometry Of Chemical Reactions
Section: Chapter Questions
Problem 91E: A sample of solid calcium hydroxide, Ca(OH)2, is allowed to stand in water until a saturated...
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2. A titration was done with H2SO4 as the analyte in the flask and AI(OH)3 as the titrant in the burette according to this equation: 3 H2SO4laq) + 2 AI(OH)3(aq) + 2 Al(OH)3(aq) ---> Al2(SO4)3(s) + 6 H2O) If 47.31 mL of 0.09847 M Al(OH)3 was used to neutralize 25.00 mL of H2SO4, what is the molarity of the H2SO4?
Transcribed Image Text:2. A titration was done with H2SO4 as the analyte in the flask and AI(OH)3 as the titrant in the burette according to this equation: 3 H2SO4laq) + 2 AI(OH)3(aq) + 2 Al(OH)3(aq) ---> Al2(SO4)3(s) + 6 H2O) If 47.31 mL of 0.09847 M Al(OH)3 was used to neutralize 25.00 mL of H2SO4, what is the molarity of the H2SO4?
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