2. The following questions refer to the pedigree chart in the figure for a family, some of whosemembers exhibit the dominant trait, W. Affected individuals are indicated by a dark square or circle.2IwwWw2 3456IIIIV123A. What is the genotype of individual II-4?B. What is the genotype of individual II-5?C. If individual II-2 and his partner have a second child, what is the probability that their secondchild will be a normal, unaffected male? Show your work:3. Phenylketonuria is an inherited disease caused by a recessive autosomal allele. If a woman and herhusband are both carriers, what is the probability that their first child will be a phenotypicallynormal female? First, draw the pedigree for this family. Then, calculate the probability (show yourwork):34. A man who is heterozygous for PTC tasting marries a woman who is homozygous recessive. Theyhave two children. Their oldest daughter is a taster, and their youngest boy is a non-taster. What isthe probability that their third child will be a taster boy? Draw a pedigree for this family:

To answer these genetic questions, I'll break down each scenario, analyze the pedigree charts, and…

Answered: 2. The following questions refer to the…

Biology: The Unity and Diversity of Life (MindTap Course List)

15th Edition

ISBN:9781337408332

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter14: Chromosomes And Human Inheritance

Section: Chapter Questions

Problem 4SQ

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Similar questions

For each genotype listed, what allele combinations will occur in gametes? a. AABBCC b. AaBBc c. AaBBcc d. AaBbCc
Which recombination frequency corresponds to perfect linkage and violates the law of independent assortment? 0 0.25 0.50 0.75
A testcross is a way to determine ________. a. phenotype b. genotype c. dominance
1. A disease is known to be inherited through an ADHL mode of inheritance. For a pairing of two affected individuals, what is the expected proportion of offspring that will be affected AND female? A. 0. B. 0.667. C. 0.333.
1. Construct a pedigree chart of the trait traced in the situation below.2. The pedigree chart must be constructed with the names and genotypes at the bottom of every individual in the chart.If it is autosomal: Always use the first letter of the dominant trait to represent the dominant allele. For example, if the dominant trait is red, so the allele R-red, while r-yellow. For example, if the person is homozygous dominant for curly hair, we write CC as his genotype. If sex-linked, do not forget to write the parents’ chromosomes (XX-female, XY-male), with their corresponding superscripts (dominant or recessive). The superscript must be based on the first letter of the disorder. For example, the mother is a carrier of hemophilia (which is x-linked recessive), so we write XHXh. If the father has hemophilia, we write XhY. Put the pedigree chart using code properly. The situation is given below: Trait: NeurofibromatosisThe dominant form is neurofibromatosis, caused by the production of…
1. Construct a pedigree chart of the trait traced in the situation below.2. The pedigree chart must be constructed with the names and genotypes at the bottom of every individual in the chart.If it is autosomal: Always use the first letter of the dominant trait to represent the dominant allele. For example, if the dominant trait is red, so the allele R-red, while r-yellow. For example, if the person is homozygous dominant for curly hair, we write CC as his genotype. If sex-linked, do not forget to write the parents’ chromosomes (XX-female, XY-male), with their corresponding superscripts (dominant or recessive). The superscript must be based on the first letter of the disorder. For example, the mother is a carrier of hemophilia (which is x-linked recessive), so we write XHXh. If the father has hemophilia, we write XhY. Put the pedigree chart using code properly. The situation is given below: Trait: NeurofibromatosisThe dominant form is neurofibromatosis, caused by the production of…
7. Mr. and Mrs. Weasley have 7 children and all of the children have red hair like their parents. Mrs. Weasley has brown eyes but Mr. Weasley's eye color is unknown. Four of their 7 children have blue eyes and three have brown eyes. a. I Mr. Weasley's eye color is blue, what must be Mrs. Weasley's genotype? Explain how you arrive at your answer. Draw a Punnett square to support your answer. Explanation
4.) A man and a woman have a child. The father is blood type A, and one of his parents was blood type A and the other was blood type O. The mother is blood type B, and one of her parents was blood type B, the other type O. Both the father and the mother are carriers of the Bombay allele. (Neither of the type-O grandparents were type O because of the Bombay allele – they had the regular type O genotype.) WhataretheoddsthattheirbabywillhavebloodtypeO? WhataretheoddsthattheirbabywillhavebloodtypeAB? (Hint – for this question, you should draw out a pedigree and fill in as much as you can for the genotypes of BOTH genes that are involved.)
4. Mr. Salazar has Type A blood while Mrs. Salazar has Type B. They have four children. Bobbie has Type A, Gabbie has Type B, Alex has Type AB, and Teddie has Type O. What are the genotypes of all six people in this family? NOTE: The ABO blood type gene has three alleles. IA and IB are codominant; i (for Type O) is recessive to both.
4) A testcross is used to determine which of the following? a) The phenotype of an individual with a dominant genotype b) The phenotype of an individual with a recessive genotype c)The genotype of an individual with a dominant phenotype d) The genotype of an individual with a recessive phenotype
1. A human female "carrier" who is heterozygous for the recessive, sex-linked trait causing red-green color blindness (or alternatively, hemophilia), marries a normal male. What proportion of their male progeny will have red-green color blindness (or alternatively, will be hemophiliac)? * a. 100% b. 75% c. 50% d. 25% e. 0% 2. A human female "carrier" who is heterozygous for the recessive, sex-linked trait red color blindness, marries a normal male.What proportion of their female progeny will show the trait? * a. All b. ½ c. ¼ d. 0 e. 3/4 3. Women have sex chromosomes of XX, and men have sex chromosomes of XY. Which of a man's grandparents could not be the source of any of the genes on his Y-chromosome? * a. Father's Mother b. Mother's Father c. Father's Father d. Mother's Mother, Mother's Father, and Father's Mother e. Mother's Mother 4. Male-pattern baldness is an example of a sex-influenced trait. The baldness allele, which causes hair loss, is influenced by the hormones…
2.In dogs, there is a hereditary deafness caused by a recessive allele, d. A kennel owner has a male dog that she wants to use for breeding purposes if possible. The dog can hear, but the owner is unsure of the genotype. She does a testcross (crosses it to a homozygous recessive dog), and two of the five offspring are deaf. This means that the male dog A.has the genotype DD B.has the genotype Dd C.is still of unknown genotype since there were offspring of both deaf and hearing phenotypes. D.has the genotype dd

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