2. Use equations (1) to (4) to calculate the enthalpy change for the reaction represented by equation (5). (1) P4 (s) + 6CI2 (g) → 4 PCI; (g) (2) P4 (s) +5 02 (g) → 4 P,O10 (g). (3) PCI3 (g) + Cl2 (g) (4) PCI3 (g) +¬02 (g) → POCI; (g) (5) PO10 (s)+6 PCI5 (g) AH =-1226 kJ AH = 2967 kJ PCI, (g) AH = 84 kJ AH=D - 286 kJ 10 РОС13 (g)

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ISBN:9780618562763
Author:Steven S. Zumdahl
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Chapter10: Energy
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Problem 31A
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2. Use equations (1) to (4) to calculate the enthalpy change for the reaction
represented by equation (5).
(1) P. (s) + 6CI2 (g) →
(2) Pa (s) +5 0 (g) → 4 P,O10 (g).
(3) PCI3 (g) +Cl2 (g) → PCI, (g)
(4) PCI3 (g) +¬O2 (g) → POCI; (g)
(5) P010 (s)+6 PCI5 (g)
4 PCI3 (g)
AH =-1226 kJ
AH = 2967 kJ
AH = 84 kJ
ΔΗ -
- 286 kJ
10 POCI3 (g)
Transcribed Image Text:2. Use equations (1) to (4) to calculate the enthalpy change for the reaction represented by equation (5). (1) P. (s) + 6CI2 (g) → (2) Pa (s) +5 0 (g) → 4 P,O10 (g). (3) PCI3 (g) +Cl2 (g) → PCI, (g) (4) PCI3 (g) +¬O2 (g) → POCI; (g) (5) P010 (s)+6 PCI5 (g) 4 PCI3 (g) AH =-1226 kJ AH = 2967 kJ AH = 84 kJ ΔΗ - - 286 kJ 10 POCI3 (g)
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