2. What is the mass of KIHP that you will weigh? 700-800m9 a The instructions read "Weigh out accurately 700 to 800 mg of KHP". Why are you given a range in the instructions and why is this acceplable? I+ iş acceptable because KH P is the excess reactant dnd therefore, you only need to haye ewough, moles of this compound but not a spečific number or mole's. 3. Why is it important to not have any bubbles in the tip of the buret? Dobles in the tip, of the buret becawse, of herwyise, the yvolvune of tit raut If is ivneorteut not to have äuy Actually added will be different from, the yolume to thie butet. If there are bubbles in the tip the volume of titraut thiat, act ually yets in contact with the analyte, will be lower trad the recorded Yolume. 4. How many milliliters of 6.0 M NAOH must be used to prepare 1.0 L of 0.10M NAOH? Show calculation with units. Given: M.Vi = M2 V2 Vi = M, V2 - 0.10( L V =! My = 0.10M V2 = IL M. VI = 0.014lalalah VI= I4.47 Vi= lle,47 wmL v SA student titrates a 25.00 mL aliquot of HCl (concentration unknown) with 33.10 mL of 0.1500 M NAOH. What is the concentration of HCI? Show calculation with units. HCl+ Ng OH -> HyO+ NaCI Mに 050()x ろる.10»1C M2 V2 20.1500( VI Mi= Given: you cannot use M,VI= 25 x 10- L MI ? V = 25 mL Mai 0.15,00M Mi =0.1906M M2V2 Concentration of Hel=D.1904M う」
2. What is the mass of KIHP that you will weigh? 700-800m9 a The instructions read "Weigh out accurately 700 to 800 mg of KHP". Why are you given a range in the instructions and why is this acceplable? I+ iş acceptable because KH P is the excess reactant dnd therefore, you only need to haye ewough, moles of this compound but not a spečific number or mole's. 3. Why is it important to not have any bubbles in the tip of the buret? Dobles in the tip, of the buret becawse, of herwyise, the yvolvune of tit raut If is ivneorteut not to have äuy Actually added will be different from, the yolume to thie butet. If there are bubbles in the tip the volume of titraut thiat, act ually yets in contact with the analyte, will be lower trad the recorded Yolume. 4. How many milliliters of 6.0 M NAOH must be used to prepare 1.0 L of 0.10M NAOH? Show calculation with units. Given: M.Vi = M2 V2 Vi = M, V2 - 0.10( L V =! My = 0.10M V2 = IL M. VI = 0.014lalalah VI= I4.47 Vi= lle,47 wmL v SA student titrates a 25.00 mL aliquot of HCl (concentration unknown) with 33.10 mL of 0.1500 M NAOH. What is the concentration of HCI? Show calculation with units. HCl+ Ng OH -> HyO+ NaCI Mに 050()x ろる.10»1C M2 V2 20.1500( VI Mi= Given: you cannot use M,VI= 25 x 10- L MI ? V = 25 mL Mai 0.15,00M Mi =0.1906M M2V2 Concentration of Hel=D.1904M う」
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter5: Resonance
Section: Chapter Questions
Problem 18E
Related questions
Question
Correct the ones that are marked wrong(2a and 5) completely and SHOW ALL CALCULATIONS:
Transcribed Image Text:2.
What is the mass of KHP that you will weigh?
700-807m9
aThe instructions read "Weigh out accurately 700 to 800 tng of KHP". Why are
you given a range in the instructions and why is this acceptable?
It is acceptable because KH P is the excess
reactaint dnd theref ure, you only need to
haye enough. moles of this compound but
speritic
not a spečific number or mole's.
Why is it important to not have any bubbles in the tip of the buret?
ubles inthe tip
It is, ivmeortaut not to have
of the outet becawe, ot hervyise, the yolvune of fit raut
actuaily Added will
Sof titrant that can be written acording to the
buret. If there are bubbles in the tip ofuthe buret,
the volume of titrant that, actvally cts in contact
with the analyte, will be lower trad thie recorded
Any
dif ferent from the yolume
volume.
How
4.
many
milliliters of 6.0 M NAOH must be used to prepare 1.0 L of 0.10 M NaOH?
Show calculation with units.
Given:
MiV, = M2
V2
Vi = M,Ve - 0.10() xIL
Vi =?
Me = 0.10M
V2 = IL
Mi
Vi = 0.01aelaleL
V= le.67 mL v
A student titrates a 25.00 mL aliquot of HCl (concentration unknown) with 33.10 mL of
0.1500 M NaOH. What is the concentration of HCI? Show caļculation with units.
HCl + Na DH -> H,0 + NaCí
Given:
MiV. M2 V2
Mi=
use MVi= Mi= 0.190&M
M2V2 Concentration of Hel=0.1904M
you cannot
VI
25 x 10-L
MI=!
VI = 25 mL
Ma= 0.15,00M
Vz = 38.10 mL=39.10x|ID L
3.
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