3 9: an induction motor with 460V, 18.65 kW, 60HZ, 4-pole, + coupled rotor winding, has the following impedance in ohms per phase reduced to the stator circuit, R1= 0.6412 R2' = 0.332 2 x1= 1,106 2 x20" 0.4642 XM= 26.3 2 (solute using Tevenin's theorem) a) what is the maximum moment of this motor Pmax? b) at what speed is the maximum moment nmax and Smax occurs when sliding c) What is the take-off moment Ist of this engine?

3 9: an induction motor with 460V, 18.65 kW, 60HZ, 4-pole, + coupled rotor winding, has the following impedance in ohms per phase reduced to the stator circuit, R1= 0.6412 R2' = 0.332 2 x1= 1,106 2 x20" 0.4642 XM= 26.3 2 (solute using Tevenin's theorem) a) what is the maximum moment of this motor Pmax? b) at what speed is the maximum moment nmax and Smax occurs when sliding c) What is the take-off moment Ist of this engine?

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Equivalent circuit parameters of 3 HP (HP) 220V, 50Hz, 6 poles, split phase wound induction motor are given below. The loss of the motor is = 4W. Since the slip is s=5%; Calculate the stator current, output torque, motor speed and efficiency. R1 = 2 , R2` = 3 , X1=0 , X2` =0 , Xm=∞
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A Y- connected, 10-KVA, 230- has a field winding resistance of 4.59. At an operation of 0.85 lagging power factor, the excitation current is recorded at 10A. the core loss is 300W, and the mechanical loss is 200W. If the corresponding efficiency is 84.9%. calculate the per- phase armature winding resistance.
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