3 An aluminum (shear modulus = 2.8× 1010 Pa) rod is 25 mm in diameter and 50 cm long. One end is rigidly fixed to a support. What torque must be applied to twist the rod 4.5° about its longitudinal axis?

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter3: Torsion
Section: Chapter Questions
Problem 3.8.8P: A solid circulai' aluminum bar AB is fixed at both ends and loaded by a uniformly distributed torque...
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3 An aluminum (shear modulus = 2.8× 1010 Pa) rod is
25 mm in diameter and 50 cm long. One end is rigidly
fixed to a support. What torque must be applied to
twist the rod 4.5° about its longitudinal axis?
Transcribed Image Text:3 An aluminum (shear modulus = 2.8× 1010 Pa) rod is 25 mm in diameter and 50 cm long. One end is rigidly fixed to a support. What torque must be applied to twist the rod 4.5° about its longitudinal axis?
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