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3 The liquid-phase reaction in Problems P11-4a and P12-7A is to be carried out in a semibatch reactor. There are 500 mol of A initially in the reactor at 25°C. Species B is fed to the reactor at 50°C and a rate of 10 mol/min. The feed to the reactor is stopped after 500 mol of B has been fed. (a) Plot and analyze the temperature Q, Qg and conversion as a function of time when the reaction is carried out adiabatically. Calculate to t = 2 h. (b) Plot and analyze the conversion as a function of time when a heat exchanger (UA = 100 cal/min·K) is placed in the reactor and the ambient temperature is constant at 50°C. Calculate to t = 3 h. (c) Repeat part (b) for the case where the reverse reaction cannot be neglected. New parameter values: k = 0.01 (dm³/mol · min) at 300 K with E = 10 kcal/mol Vo 50 dm³, vo = 1 dm³/min, CA0 = C30 = 10 mol/dm³ For the reverse reaction: k. = 0.1 min-1 at 300 K with E. = 16 kcal/mol =

3 The liquid-phase reaction in Problems P11-4a and P12-7A is to be carried out in a semibatch reactor. There are 500 mol of A initially in the reactor at 25°C. Species B is fed to the reactor at 50°C and a rate of 10 mol/min. The feed to the reactor is stopped after 500 mol of B has been fed. (a) Plot and analyze the temperature Q, Qg and conversion as a function of time when the reaction is carried out adiabatically. Calculate to t = 2 h. (b) Plot and analyze the conversion as a function of time when a heat exchanger (UA = 100 cal/min·K) is placed in the reactor and the ambient temperature is constant at 50°C. Calculate to t = 3 h. (c) Repeat part (b) for the case where the reverse reaction cannot be neglected. New parameter values: k = 0.01 (dm³/mol · min) at 300 K with E = 10 kcal/mol Vo 50 dm³, vo = 1 dm³/min, CA0 = C30 = 10 mol/dm³ For the reverse reaction: k. = 0.1 min-1 at 300 K with E. = 16 kcal/mol =

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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From Elements of CRE by Fogler - 2016

P13-3B The liquid-phase reaction in Problems P11-4A and P12-7A is to be carried out in a semibatch reactor. There are 500 mol of A initially in the reactor at 25°C. Species B is fed to the reactor at 50°C and a rate of 10 mol/min. The feed to the reactor is stopped after 500 mol of B has been fed. (a) Plot and analyze the temperature Q, Q̟ and conversion as a function of time when the reaction is carried out adiabatically. Calculate to t = 2 h. (b) Plot and analyze the conversion as a function of time when a heat exchanger (UA = 100 cal/min · K) is placed in the reactor and the ambient temperature is constant at 50°C. Calculate to t = 3 h. (c) Repeat part (b) for the case where the reverse reaction cannot be neglected. New parameter values: 0.01 (dm³/mol · min) at 300 K with E = 10 kcal/mol V, = 50 dm³, v, = 1 dm/min, CA0 = CB0 = 10 mol/dm³ For the reverse reaction: k, = 0.1 min¬1 at 300 K with E, k = 16 kcal/mol
Transcribed Image Text:P13-3B The liquid-phase reaction in Problems P11-4A and P12-7A is to be carried out in a semibatch reactor. There are 500 mol of A initially in the reactor at 25°C. Species B is fed to the reactor at 50°C and a rate of 10 mol/min. The feed to the reactor is stopped after 500 mol of B has been fed. (a) Plot and analyze the temperature Q, Q̟ and conversion as a function of time when the reaction is carried out adiabatically. Calculate to t = 2 h. (b) Plot and analyze the conversion as a function of time when a heat exchanger (UA = 100 cal/min · K) is placed in the reactor and the ambient temperature is constant at 50°C. Calculate to t = 3 h. (c) Repeat part (b) for the case where the reverse reaction cannot be neglected. New parameter values: 0.01 (dm³/mol · min) at 300 K with E = 10 kcal/mol V, = 50 dm³, v, = 1 dm/min, CA0 = CB0 = 10 mol/dm³ For the reverse reaction: k, = 0.1 min¬1 at 300 K with E, k = 16 kcal/mol
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