3. The rates of a carbonic anhydrase catalyzed reaction of CO2 and H2O, in the absence and presence of an inhibitor (I), are measured and given below. The initial concentration of the enzyme carbonic anhydrase was 20 mM, and the initial concentration of the inhibitor concentration was 6.0 mM. (Attach any necessary graphs) R. (M s) R. (M s4) [S]. (M) No inhibitor With Inhibitor 1.00E-03 1.76E-06 1.17E-06 2.00E-03 2.50E-06 1.45E-06 5.00E-03 3.34E-06 1.70E-06 1.00E-02 3.77E-06 1.81E-06 2.00E-02 4.02E-06 1.86E-06 a) Determine the mode of inhibition b) Calculate the values of Km, Ki, Rmax, k2.
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- The equation of the double reciprocal plot is y = 0.5294 x + 1.4960. What is the value of vmax (in M/s)? The substrate concentration is given in units of molarity (M) and reaction velocity has units of molarity per second (M/s). (Report to three significant figures)6. If inhibitor X changes lactase activity to a Vo of 0.333333333333 mM per minute when [S] = 2.0 mM, and a Vo of 0.50 mM per minute when [S] = 3.33333333333 mM, calculate the new Vmax. 1.0 mM per minute 2.0 mM per minute 2.5 mM per minute 5.0 mM per minute 10.0 mM per minute 7. Calculate the new Km of the lactase reaction with inhibitor X. 1.0 mM 2.0 mM 2.5 mM 5.0 mM 10.0 mM 8. Calculate the slope on a Lineweaver-Burk plot (Km / Vmax) for the lactase reaction with inhibitor X. 1.0 per minute 2.0 per minute 2.5 per minute 5.0 per minute 10.0 per minute Inhibitor X exerts which of the following effects on the above enzyme (lactase)? uncompetitive inhibition mixed noncompetitive inhibition competitive inhibition pure noncompetitive inhibition all of the above1) How is the TCA cycle regulated? a) Draw the TCA diagram that fills in all possible regulation points.
- The free energy of hydrolysis for acetic anhydride is221.8 kJ/ mol. The conversion of ATP to ADP also involvesthe cleavage of an anhydride bond. Its free energy of hydrolysis is 230 kJ/ mol. Explain the difference in these values.1.In a kinetics data set, in case a substrate concentration is given [S] in uM and inhibitor concentration [I] uM, initial velocity (Vo) in umol/min , Km , Vmax, apparent Km, apparent Vmax, and Ki, is there any way of finding Kcat ? 2.Which formula would be used in that case? What would the process be for finding Kcat?10. For the situations described below, indicate whether KM , Vmax, both parameters, orneither parameter would be altered. Assume that [S] in in excess.(a) After [S] has been doubled(b) In the presence of a competitive inhibitor(c) After the [E] has been doubled
- A new drug, Proinebrium, that reduces Kcat (Ki = 2.0 uM) has been developed to treat ethylene glycol poisoning. (1) What concentration of Proinebrium is required to achieve 50% inhibition of ethylene glycol metabolism by alcohol dehydrogenase when the concentraion of ethlyene glycol in the blood is 50 uM?1. Bypass reaction in the anabolic pathway often occurs when A The ΔG of the reverse reaction in the catabolic pathway has a large negative value B The ΔG of the reverse reaction in the catabolic pathway has a large positive value C The ΔG of the reaction in the anabolic pathway is close to zero D The ΔG of the reaction in the anabolic pathway is positive E None of the aboveThe Ki for a competitive inhibitor pyrrole-2-carboxylate is 0.05M.Calculate the initial velocity if the substrate concentration is 0.25M and 1.0 mole/liter of the inhibitor is added to thereaction.
- 1 the concentration of the enzyme competition inhibitor was 1×10-3M. If 1 µmol of the inhibitor is present inthe 1 mL reaction mixture, Indicate how much the initial degree of hydrolysis decreases as a proportion(in thepresence of inhibitors/in the absence of inhibitors) with respect to the absence of inhibitors.A researcher wants to look for glucaronic acid conjugated metabolites in sample of urine(glucaronic acid conjugation is a common method of metabolism for excretion.) Pronotated glucaronic acid conjugated metabolite ions often lose anhydroglucaronic acid(176 Da) during low energy CID. Which triple quadrupole experiment might be best for finding these conjugates?Which of the following statements is true about the chymotrypsin reaction? 1. The catalytic triad at the active site is formed by three residues: His, Gly, and Ser 2. When the substrate is p-Nitrophenylacetate, the rate-limiting step is the release of p-Nitrophenolate. 3. During the reaction, LBHB forms when the proton is donated to His from Ser or water. 4. The chymotrypsin reaction involves “only” specific acid-base catalysis 5. The “oxyanion hole” is formed by the amide nitrogens of Ser and Glu