4. The equilibrium constant (Kp) for the following reaction is 0.113 at 298 K, which corresponds to a standard free-energy change of 5.40 kJ/mol. In a certain experiment, the initial pressures are PNO2 = 0.122 atm and PN204 = 0.453 atm. Calculate AG for the reaction at these pressures and predict the direction of the net reaction at equilibrium, take the gas constant (R) value as 8.314 J/K.mol. N204(g) → 2NO2(g)

Chemistry: Principles and Reactions
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Chapter16: Spontaneity Of Reaction
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4. The equilibrium constant (Kp) for the following reaction is 0.113 at 298 K, which
corresponds to a standard free-energy change of 5.40 kJ/mol. In a certain experiment, the
initial pressures are PNO2 = 0.122 atm and PN204 = 0.453 atm. Calculate AG for the reaction at
these pressures and predict the direction of the net reaction at equilibrium, take the gas
constant (R) value as 8.314 J/K.mol.
N204(g)
→ 2NO2(g)
Transcribed Image Text:4. The equilibrium constant (Kp) for the following reaction is 0.113 at 298 K, which corresponds to a standard free-energy change of 5.40 kJ/mol. In a certain experiment, the initial pressures are PNO2 = 0.122 atm and PN204 = 0.453 atm. Calculate AG for the reaction at these pressures and predict the direction of the net reaction at equilibrium, take the gas constant (R) value as 8.314 J/K.mol. N204(g) → 2NO2(g)
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