4. Use the following information to answer the questions below. PEP + ADP → Pyruvate + ATP (AG" = -6.62kcal/mol) R= 1.987 cal/mol K T= 24°C [PEP] = .05 M [Pyruvate] = .01M [ATP]/[ADP] = 2.5 %3D а. What is the equilibrium constant for this reaction? SHOW YOUR WORK! thanks b. What is the AG in this cell under these conditions? SHOW YOUR WORK! thanks

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section: Chapter Questions
Problem 10QRT
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4. Use the following information to answer the questions below.
PEP + ADP > Pyruvate + ATP (AG" = -6.62kcal/mol)
R= 1.987 cal/mol K
T= 24°C
[PEP] = .05 M [Pyruvate] = .01M
[ATP]/[ADP] = 2.5
а.
What is the equilibrium constant for this reaction? SHOW YOUR WORK! thanks
b.
What is the AG in this cell under these conditions? SHOW YOUR WORK! thanks
Transcribed Image Text:4. Use the following information to answer the questions below. PEP + ADP > Pyruvate + ATP (AG" = -6.62kcal/mol) R= 1.987 cal/mol K T= 24°C [PEP] = .05 M [Pyruvate] = .01M [ATP]/[ADP] = 2.5 а. What is the equilibrium constant for this reaction? SHOW YOUR WORK! thanks b. What is the AG in this cell under these conditions? SHOW YOUR WORK! thanks
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