5. A 92.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 50.0 m/s. If both are initially at rest and if the ice is frictionless, how far (in m) does the player recoil in the time it takes the puck to reach the goal 19.0 m away? (Enter the magnitude.) Ans: 0.031irth rom behine p> player pu → Puck O-MoVpt Mpu Vpu t* Mo ve =-Mpa Vou Mev - Μpu ν 0.15x So %3D F008 Mb doveNel= 0:08M time tor puck = 92V 19W 50 player recoil distance こUxtニo、08x0.38 %3D ctime cof fer player 6. A bullet is accelerated down the harrol of 3151n

University Physics Volume 1
18th Edition
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Author:William Moebs, Samuel J. Ling, Jeff Sanny
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Chapter9: Linear Momentum And Collisions
Section: Chapter Questions
Problem 45P: A 90.0-kg ice hockey player hits a 0.150-kg puck, giving the puck a velocity of 45.0 m/s. If both...
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5. A 92.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity
of 50.0 m/s. If both are initially at rest and if the ice is frictionless, how far (in m) does
the player recoil in the time it takes the puck to reach the goal 19.0 m away? (Enter
the magnitude.)
Ans: 0.031irth
rom
behine
p> player pu → Puck
O-MoVpt Mpu Vpu t*
Mo ve =-Mpa Vou
Mev
- Μpu ν
0.15x So
%3D
F008
Mb
doveNel= 0:08M time tor puck =
92V
19W
50
player
recoil distance
こUxtニo、08x0.38
%3D
ctime cof fer
player
6. A bullet is accelerated down the harrol of
3151n
Transcribed Image Text:5. A 92.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 50.0 m/s. If both are initially at rest and if the ice is frictionless, how far (in m) does the player recoil in the time it takes the puck to reach the goal 19.0 m away? (Enter the magnitude.) Ans: 0.031irth rom behine p> player pu → Puck O-MoVpt Mpu Vpu t* Mo ve =-Mpa Vou Mev - Μpu ν 0.15x So %3D F008 Mb doveNel= 0:08M time tor puck = 92V 19W 50 player recoil distance こUxtニo、08x0.38 %3D ctime cof fer player 6. A bullet is accelerated down the harrol of 3151n
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