The vector position of a 4.00 g particle moving in the xy plane varies in time according to r, = (3î + 3j)t + 2ĵt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.55 g particle varies as r, = 3î - 2ît? – 6jt. (a) Determine the vector position (in cm) of the center of mass of the system att = 2.60 s. -5.975i – 0.286j) cm 'cm (b) Determine the linear momentum (ing. cm/s) of the system att = 2.60 s. p = -45.72i ´+ 20.3j g. cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.60 s. 4.78i + 2.125j physF cm/s cm Operat Symbo (d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.60 s. Relatic 品 a cm cm/s? Sets In Vector Trig (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.60 s. 10 log Greek net = (-4.8)i+ (2.1)j uN O Help o!

Q: A 1.76 kg particle has the xy coordinates (-1.41 m, 0.619 m), and a 5.63 kg particle has the xy…

A: m1 = 1.76 kg r1 = (-1.41 , 0.619) m m2 = 5.63 kg r2 = (0.206 , -0.607) m m3 =3 kgrc.m= (-0.848 ,…

Q: The vector position of a 4.00 g particle moving in the xy plane varies in time according to r, = (3î…

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Q: A 5.00 kg particle has the xy coordinates (1.20 m, 2.00 m), and a 6.00 kg particle has the xy…

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A: Ans:- Image-1

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A: The system would be in equilibrium when the net force acting on the system is equal to zero. m1=1.33…

Q: The vector position of a 3.30 g particle moving in the xy plane varies in time according to r. = (31…

A: Given:  m1 = 3.3 g   r1 ⇀ = 3 t i^ +3 t + 2 t 2 j^     ⇒ v1 ⇀=dr1 ⇀dt = 3 i^ +3+ 4 t  j^     ⇒ a1…

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A: Given, A particle having mass m1=2.5 kg has coordinate x1,y1=-1.20m,0.500m A particle having mass…

Q: The vector position of a 3.65 g particle moving in the xy plane varies in time according to r, = (31…

A: To determine,Part athe vector position of the center of mass of the system at t=2.80 s.given,m1=3.65…

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Q: The vector position of a 3.50-g particle moving in the xy plane varies in time according to r→1 =…

A: Hai, since there are multiple sub parts posted, we will answer the first three sub parts. (a)

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Q: The vector position of a 3.45 g particle moving in the xy plane varies in time according to i, = (31…

A:

Q: A system of four particles moves along one dimension. The center of mass of the system is at rest,…

A:

Q: A 2.00 kg particle has the xy coordinates (1.20 m, 0.500 m), and a 4.00 kg particle has the xy…

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Q: Four objects are situated along the y axis as follows: a 2.00-kg object is at +3.00 m, a 3.00-kg…

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Q: A system of four particles moves along one dimension. The center of mass of the system is at rest,…

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Q: Block 1 of mass m1 slides along a frictionless floor and into a one-dimensional elastic collision…

A: mass of first block = m1  mass of second block, m2= 3 m1  initial velocity of second block, u2 = 0…

Q: 2. Two small-sized objects are placed on a uniform 9.00 kg plastic beam 3.00 m long, as shown in…

A: "As per the guidelines i solved the first question alone". (a) Find the location of the center of…

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Q: The vector position of a 3.80 g particle moving in the xy plane varies in time according to r, = (31…

A: The solution is given below

Q: 2. Two small-sized objects are placed on a uniform 9.00 kg plastic beam 3.00 m long, as shown in…

A: (given) m1=8 kgm2=7.50 kgM = 9 kgL = 3 mLocation of centre of mass is given byxcm =…

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Q: "A three particle system with with masses: m1 = 5.0 Kg, m2 = 3.0 Kg and m3 = 5.0 Kg. The position…

A: Given: A three-particle system has the masses (m1, m2, and m3) 5 Kg, 3 Kg, and 5 Kg respectively.…

Q: The vector position of a 3.45 g particle moving in the xy plane varies in time according to i, - (3i…

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: A system of four particles moves along one dimension. The center of mass of the system is at rest,…

A:

Q: A 2.34 kg particle has the xy coordinates (-1.81 m, 0.340 m), and a 3.82 kg particle has the xy…

A: Given data- mass m1=2.34 kg,   x1,y1=-1.81 m,0.340 m mass m2=3.82 kg,  x2,y2=0.104 m,-0.143 m mass…

Q: Three particles have masses and position vectors as follows: Ul b M 1 = i+2}-3k 72 = 4i – j 73 = 3j+…

A: Given: masses are m1 = 3 kg, m2 = 1 kg and m3 = 5 kg r1 = i + 2j  - 3k r2 = 4i - j r3 = 3j + 4k