The vector position of a 3.65 g particle moving in the xy plane varies in time according to r, = (31 + 3j)t + 2jt? where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.45 g particle varies as r, = 31 - 2ît2 - 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.80 s. rem - 5.16i – 9.98j cm (b) Determine the linear momentum (in g · cm/s) of the system at t = 2.80 s. -50.1i+ 19.1j 9• cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.80 s. = -5.50i + 2.10j cm/s cm (d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.80 s. cm/s? "cm (e) Determine the net force (in pN) exerted on the two-particle system at t = 2.80 s. Fnet

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