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7. A galvanic cell at 25°C consists of an electrode of zinc in a 0.10 M ZNSO4 solution and anther of nickel in a 0.05 M NiS04 solution. The two electrodes are separated by a porous wall and connected by an external wire. What is the emf of the cell when a switch between the two electrodes is just closed? Assume that for M→ M** +ne', the Nernst equation can be written as: e = e° + (0.059/n)×log(molar concentration of ions) e° (Zn²"/Zn) = -0.762 V and e° (Ni²*/Ni) =-0.250 V

7. A galvanic cell at 25°C consists of an electrode of zinc in a 0.10 M ZNSO4 solution and anther of nickel in a 0.05 M NiS04 solution. The two electrodes are separated by a porous wall and connected by an external wire. What is the emf of the cell when a switch between the two electrodes is just closed? Assume that for M→ M** +ne', the Nernst equation can be written as: e = e° + (0.059/n)×log(molar concentration of ions) e° (Zn²"/Zn) = -0.762 V and e° (Ni²*/Ni) =-0.250 V

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter17: Electrochemistry
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7. A galvanic cell at 25°C consists of an electrode of zinc in a 0.10 M ZnSO4 solution and anther of nickel in a 0.05 M NiS04 solution. The two electrodes are separated by a porous wall and connected by an external wire. What is the emf of the cell when a switch between the two electrodes is just closed? Assume that for M → M** +ne', the Nernst equation can be written as: e = e° + (0.059/n)×log(molar concentration of ions) e° (Zn²"/Zn) = -0.762 V and e° (Ni²*/Ni) = -0.250 V
Transcribed Image Text:7. A galvanic cell at 25°C consists of an electrode of zinc in a 0.10 M ZnSO4 solution and anther of nickel in a 0.05 M NiS04 solution. The two electrodes are separated by a porous wall and connected by an external wire. What is the emf of the cell when a switch between the two electrodes is just closed? Assume that for M → M** +ne', the Nernst equation can be written as: e = e° + (0.059/n)×log(molar concentration of ions) e° (Zn²"/Zn) = -0.762 V and e° (Ni²*/Ni) = -0.250 V
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