9.83 Toxic Mushrooms? Cadmium, a heavy metal, is toxic to ani-mals. Mushrooms, however, are able to absorb and accumulate cad-mium at high concentrations. The Czech and Slovak governmentshave set a safety limit for cadmium in dry vegetables at 0.5 part permillion (ppm). M. Melgar et al. measured the cadmium levels in arandom sample of the edible mushroom Boletus pinicola and pub-lished the results in the paper "Influence of Some Factors in Toxicityand Accumulation of Cd from Edible Wild Macrofungi in NW Spain"(Journal of Environmental Science and Health, Vol. B33(4), pp. 439-455). Here are the data.0.240.920.590.191.330.62 0.16 0.770.33 0.25 0.59 0.32At the 5% significance level, do the data provide sufficient evi-dence to conclude that the mean cadmium level in Boletus pinicolamushrooms is greater than the government's recommended limit of0.5 ppm? Assume that the population standard deviation of cadmium levels in Boletus pinicola mushrooms is 0.37 ppm. (Note: The sumof the data is 6.31 ppm.)

The given sample size is 12, sum of the samples is 6.31, population standard deviation is 0.37.

Answered: 9.83 Toxic Mushrooms? Cadmium, a heavy…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A study was conducted to determine if lung cancer altered levels of surfactant in the alveoli of the lung. Seven healthy subjects in the study yielded the following data on surfactant levels: 18, 12, 15, 15, 16, 9, 17. Seven lung cancer patients yielded the following results: 16, 8, 7, 15, 11, 12, 9. Do these data indicate a difference in the surfactant level with cancer? Let α = 0.05. Give the p-value.
The authors of a paper classified characters who were depicted smoking in movies released between a certain range of years. The smoking characters were classified according to sex and whether the character type was positive, negative, or neutral. The resulting data are summarized in the accompanying table. Assume that it is reasonable to consider this sample of smoking movie characters as representative of smoking movie characters. Do the data provide evidence an association between sex and character type for movie characters who smoke? Use α = 0.05. Sex = Male Female Positive Negative Neutral 256 Character Type 85 107 11 132 51 Calculate the test statistic. (Round your answer to two decimal places.) x² Use technology to calculate the P-value. (Round your answer to four decimal places.) P-value = What can you conclude? O Reject Ho. There is convincing evidence to conclude that there is an association between sex and character type for movie characters who smoke. Fail to reject Ho.…
11.8 Fast-food. If you go to the website for any fast-food chain, you can generally find information about the nutritional content of menu items. In February 2019, a sample of 130 menu items was selected from 13 popular fast-food chains, and the amount of carbohydrates (measured in grams) was recorded for each of these items. Figure 11.10 shows the distribution of grams of carbohydrates from the 130 menu items. Describe the shape, center, and variability of this distribution. Are there any outliers? 40 30 20 10 20 40 60 80 100 120 140 Total carbohydrates (in grams) Moore/Notz, Statistics: Concepts and Controversies, 1Oe, © 2020 W. H. Freeman and Company Frequency
14.34 Gutsell (1951) measured hemoglobin in the blood of brown trout after treat- ment with four rates of sulfamerazine. Two methods of administering the sul- famerazine were used. Ten fish were measured for each rate and each method. The data are given in Table 14.7. Test for effect of rate and method and interaction.
A researcher conducts a two-year study comparing the number of cavities in a group of 30 randomly selected young children from the community before and after the application of fluoride to test if there is a decrease in the number of cavities. This is an example of a/an: Independent-samples t test or Dependent-samples t test?
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Lecture(8.8): The amount of time people engage in physical activity mat be related to health outcome. Those who report that they spend more than 15 hours are put into one while those who spend less 10 were put into another group. (Those who fall in between 10 and 15 were left out of the study); The reaearcher then ask the participants to wear a monitor for one month. The average time in minutes is recorded and shown below . Is there any evidence that on average people who watch less than 10 hours watching televsion spend more time on physical activity.?. Test the hypotheses at (alpha=0.05) using the 5 step procedure <10 hours 75 63 118 35 82 >15 hours 62 6 78 43 22 33
Give answer from the choice and explain it as given in image. Note:hand written solution not allowed.
Inorganic phosphorous is a naturally occurring element in all plants and animals, with concentrations increasing progressively up the food chain (fruit < vegetables < cereals < nuts < corpse). Geochemical surveys take soil samples to determine phosphorous content (in ppm, parts per million). A high phosphorous content may or may not indicate an ancient burial site, food storage site, or even a garbage dump. Independent random samples from two regions gave the following phosphorous measurements (in ppm). Assume the distribution of phosphorous is mound-shaped and symmetric for these two regions. REGION I:X1;N1=15 857 1,551 1,230 875 1,080 2,330 1,850 1,860 2,340 1,080 910 1,130 1,450 1,260 1,010 REGION II:X2;N2=14 538 812 790 1,230 1,770 960 1,650 860 890 640 1,180 1,160 1,050 1,020 (a) Use a calculator with mean and standard deviation keys to verify that x1, s1, x2, and s2. (Round your answers to four decimal places.) x1= ppm s1= ppm x2= ppm s2= ppm…
Hexavalent chromium has been identified as an inhalation carcinogen and an air toxin of concern in a number of different locales. A sample of 12 randomly selected houses from a certain region was tested for hexavalent chromium concentration (nanograms/m3) in the indoor and outdoor. House Indoor Outdoor 1 0.07 0.29 2 0.08 0.68 3 0.09 0.47 4 0.12 0.35 5 0.13 0.49 6 0.15 0.86 7 0.17 0.32 8 0.20 1.59 9 0.22 0.52 10 0.23 0.88 11 0.26 0.49 12 0.28 1.11 Let μd=indoor−outdoorμd=indoor−outdoor. a. What is the mean difference d¯d¯? Use up to 4 decimal places. b.What is the standard deviation of the differences sdsd? Use up to 4 decimal places. c.What is the 98% confidence interval estimate for the mean difference in hexavalent chromium concentration between indoors and outdoors?

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