_P4(s) + __Cl2(g) --> __PCl5(g) H°rxn = –1500 kJ In a reaction mixture of 0.22 g(P4) and 1.45 g(Cl2): The 0.22 grams of P4 are enough to form _______ mol (PCl5)_______ LSTP (PCl5) The 1.45 grams of Cl2 are enough to form _______ mol (PCl5)_______ LSTP (PCl5) The limiting reagent (LR) in the mixture is _______
_P4(s) + __Cl2(g) --> __PCl5(g) H°rxn = –1500 kJ In a reaction mixture of 0.22 g(P4) and 1.45 g(Cl2): The 0.22 grams of P4 are enough to form _______ mol (PCl5)_______ LSTP (PCl5) The 1.45 grams of Cl2 are enough to form _______ mol (PCl5)_______ LSTP (PCl5) The limiting reagent (LR) in the mixture is _______
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter9: Chemical Quantities
Section: Chapter Questions
Problem 12CR: What is meant by a limiting reactant in a particular reaction? In what way is the reaction...
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__P4(s) + __Cl2(g) --> __PCl5(g) H°rxn = –1500 kJ
In a reaction mixture of 0.22 g(P4) and 1.45 g(Cl2):
The 0.22 grams of P4 are enough to form _______ mol (PCl5)_______ LSTP (PCl5)
The 1.45 grams of Cl2 are enough to form _______ mol (PCl5)_______ LSTP (PCl5)
The limiting reagent (LR) in the mixture is _______
The theoretical yield of PCl5 is _______ mol and _______ LSTP (liters at STP)
If 0.12 LSTP(PCl5) was isolated, the percent reaction yield is _______%
The most heat this reaction mixture can form is _______ kJ
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