A 0.0452 L solution of HCl is titrated with 0.0356 L of 0.0125 M Na3PO4 according the equation shown below. What is the original concentration of the 0.0452 L solution of HCl? 3 HCl (aq) + Na3PO4 (aq) --> 3 NaCl (aq) + H3PO4 (aq)
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A 0.0452 L solution of HCl is titrated with 0.0356 L of 0.0125 M Na3PO4 according the equation shown below. What is the original concentration of the 0.0452 L solution of HCl?
3 HCl (aq) + Na3PO4 (aq) --> 3 NaCl (aq) + H3PO4 (aq)
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