() FacebookC Sample Problem:C Solved: A 10.00 Gpook.com/messenger_media/?thread_id=100006994203669&attachment_id=5720744005210678emessage_id=mid.%24cAAAB8JTHra-GLYZIWE_ECAWRL-nb Answered: A standb My Questions | baO (1) FacebooSample Problems> A 10.00-g sample containing an analyte wastransferred to a 250-mL volumetric flask anddiluted to volume. When a 10.00-mL aliquot of the10 g20m330,235resulting solution was diluted to 25.00 mL it wasfound to give a signal of o.235 (arbitrary units). AlomL25 mLsecond 10.00-mL aliquot was spiked with 10.00 mLof a 1.00- ppm standard solution of the analyte anddiluted to 25.00 mL. The signal for the spiked* yss sample was found to be o.502. Calculate the weightpercent of analyte in the original sample.- 0.5 225 MLAns: 5.50 x 10-2%wearch

Solution - According to the question - Given - In the spiked sample, the signal is due to 10 ml of…

A 10.00-g sample containing an analyte was transferred to a 250-mL volumetric flask and į diluted to volume. When a 10.00-mL aliquot of the resulting solution was diluted to 25.00 mL it was 0,235 found to give a signal of o.235 (arbitrary units). A second 10.0o-mL aliquot was spiked with 10.00 mL of a 1.00- ppm standard solution of the analyte and diluted to 25.00 mL. The signal for the spiked sample was found to be o.502. Calculate the weight percent of analyte in the original sample.

A 10.00-g sample containing an analyte was transferred to a 250-mL volumetric flask and į diluted to volume. When a 10.00-mL aliquot of the resulting solution was diluted to 25.00 mL it was 0,235 found to give a signal of o.235 (arbitrary units). A second 10.0o-mL aliquot was spiked with 10.00 mL of a 1.00- ppm standard solution of the analyte and diluted to 25.00 mL. The signal for the spiked sample was found to be o.502. Calculate the weight percent of analyte in the original sample.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…
There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…
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