A 1450-kg sports car (including the driver) crosses the rounded top of a hill (radius = 88.0 m) at 20.0 m/s. - Determine the normal force exerted by the road on the car. - Determine the normal force exerted by the car on the 74.0-kg driver. - Determine the car speed at which the normal force on the driver equals zero.
Angular speed, acceleration and displacement
Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.
Angular Position
Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.
A 1450-kg sports car (including the driver) crosses the rounded top of a hill (radius = 88.0 m) at 20.0 m/s.
- Determine the normal force exerted by the road on the car.
- Determine the normal force exerted by the car on the 74.0-kg driver.
- Determine the car speed at which the normal force on the driver equals zero.
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Given: A 1450-kg sports car (including the driver) crosses the rounded top of a hill (radius = 88.0 m ) at 20.0 m/s.
1.) Determine the normal force exerted by the road on the car. (3 sig figs)
2.) Determine the normal force exerted by the car on the 74.0-kg driver. where 1450 is weight of the sports car including the driver. (3 sig figs)
(Incorrect: 14500, -14500)
3.) Determine the car speed at which the normal force on the driver equals zero. (3 sig figs)
(Incorrect answers: 14.2 m/s
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