A 21.47-mL sample of hydrochloric acid solution requires 35.00 mL of 0.109 M sodium hydroxide for complete neutralization. What is the concentration of the original hydrochloric acid solution? M
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- In which situation(s) is it necessary to use a volumetric flask for maximum accuracy? to prepare a 0.150M solution of sodium chloride to measure ~25mL of water to prepare 0.1M HCI from 36-38% HCI a and c all of the above (Please type answer no write by hend)Volume of 0.200M K2C2O4 Is required to react completely with 30.0 ML of 0.100 M Fe (NO3)3 Choose one A. 15.0 ml B. 10.0 ml C. 30.0 ml D. 22.5 mlSubmit a clean, dry, and properly labeled 50-mL reagent bottle for your unknown solution. Pipet 20.00 mL of the sample in 250-mL Erlenmeyer flask. Add 5 mL of buffer and 5 drops of indicator. Titrate the solution until it turns light blue. If the titration consumes more than 50 mL of the titrant, dilute the sample accordingly. Compute for ppm of CaCO3 using the following table. Mean Molarity = 2.487 x 10^-3 MBlank correction = 0.015 Formula = V (mL) titrant x Mean Molarity of Titrant x Molecular weight of CaCO3 x 1/V (L) sample
- It is known that acid content has a major effect on theflavor of vinegars, but most cheaper vinegars are diluted similarly to 5% acidity Wt./vol. % is equivalent to gsolute per 100mL solution (so 5% is equivalent to 5 g acid/100 mL solution). a.) First, calculate the approximate molar concentration of acetic acid in the 5% wt./vol vinegar. b.) Next, calculate the expected molarity of acetic acid in the solution upon dilution by a factor of 5. Thank you!A solution of sulfuric acid was made by dissolving 20.0g of 98% sulfuric acid in a 250mL of water. (H2SO4 = 98.078 g/mol; H2O = 18.015 g/mol)Additional information for 35-37 What if the solution has a total volume of 262ml? 1. Express the concentration of this solution in % by weight.a. 7.3%b. 4.4%c. 8.0%d. 7.8% 2. Express the concentration in molaritya. 0.10 Mb. 2.00 Mc. 0.76 Md. 0.93 M 3. Express the concentration in normalitya. 2.0 Nb. 1.5 Nc. 1.0 Nd. 0.76 N 4. Express the concentration in molalitya. 0.80 mb. 0.77 mc. 1.00 md. 1.50 mPre Lab Questions: (Each answer is to be written as a complete sentence) What is the reason for washing the precipitate with water in Step 9? Define precipitate. Define filtrate. In Step 2, what is the purpose for rinsing the stirring rod? read the Procedure to answer the questions Using a balance, mass between 1.50 – 2.00 grams of sodium carbonate in a pre-massed 150mL beaker. Add 20 mL of distilled water and stir thoroughly to make sure all the crystals are dissolved. Rinse the stirring rod with a little distilled water after stirring. Using a balance, mass between 1.50 – 2.00 grams of calcium chloride dihydrate in a pre-massed 50 mL beaker. Repeat Step 2 for the solution in the 50 mL beaker. Pour the calcium chloride solution into the 150mL beaker containing the sodium carbonate solution and stir. Mass a piece of filter paper. Fold the filter paper and place it into the funnel. Wet it with a little distilled water to ensure that it is stuck to the sides of the funnel. Slowly…
- Please answer as soon as possible. Thank you! A 10.000-g cocoa powder sample was dissolved in concentrated acid and then diluted to 100.00 mL using distilled water. The solution was found to contain 5.45 uM Fe. Calculate concentration of Fe (MM: 55.845) in the cocoa powder sample in parts-per-million (ppm) (weight by volume).Pls do fast and i will rate instantly for sure Solution must be in typed form A 25.0 mL volume of 0.0106 M KIO3 is pipetted into a 250-mL Erlenmeyer flask. The solution is titrated to the stoichiometric point with 16.25 mL of a sodium thiosulfate solution. What is the molar concentration of the sodium thiosulfate solution?At a certain temperature BaF2 has Ksp = 1.7 x 10-6.A solution of concentrated NaF is added dropwise to a solution that is 0.0144 M in Ba2+. What will the concentration of F- be when BaF2 starts precipitating. Neglect volume changes.Provide your answer in E-notation, rounded to 2 significant digits.
- A local company sent you their green alternative for window cleaner to be tested for percent (w/v) acetic acid content. For your experiment, you first standardized your NaOH titrant with 0.8053 g of (99.80 % purity) KHP. You used 40.60 mL of NaOH for your standardization. After that you then analyzed a 10.00 mL sample and found that you needed 43.20 mL NaOH to reach the end point. Summary of results: Standardization Sample analysis KHP Weight (g) 0.8053 g Volume of sample 50.00 mL Purity 99.80% NaOH (mL) used 33.20 mL NaOH (mL) used 40.60 mL Determine the following: Molarity of NaOH % (w/v) acetic acidA 25mL volumetric pipet is used to deliver a sample of the stock solution marked “0.6000M X2SO4” into a 100mL volumetric flask. Distilled water is added to the flask until it is about 3/4thfull, the solution is mixed well, then more water is added to fill it up to the calibration mark, then it is mixed again. Calculate the concentration of X+ion in the dilute solution made above.PS. Further values required for the solvings are give in the various situations below. (ANSWER) Situation: A community in a mountainous area of Bohol uses water collected from a nearby natural spring. A sample was submitted to a laboratory for the analysis of its total hardness. Required: SHOW YOUR COMPLETE CALCULATIONS. BASED ON THE IMAGE PROVIDED BELOW FOR THIS QUESTION: Calculate the amount of titrant used in each trial to reach endpoint. Report total hardness of the sample as mean ±sd. a. 250.0 mL of 500.0 ppm of CaCO3 solution from a primary standard (assume solvent is distilled water only). Answer : Mass of CaCO3 = 0.125 g b, The EDTA solution was standardized by titrating it with a 25.0 mL aliquot of the CaCO3 solution. How much of the titrant was consumed. Answer: Volume of EDTA consumed = 12.405 g c. Calculate the average titer (mg CaCO3/mL EDTA). Mass of CaCO3 in 25 mL CaCO3 solution: 0.0125 g Answer: 1.008 mg CaCO3/ mL EDTA