A 95 kg sled with a Xmas gift box of 5 kg pushed up horizontal surface together against a spring constant of 2000 N.  When the spring is released, the sled and the gift box together move along a horizontal surface and then keep moving on a ramp with friction. The ramp is 5m high (measured in vertical distance) and the coefficient friction is 0.2.When the sled and the gift box reach up to the top of the ramp, the sled get stuck and gits box fly up in the air an additional 10 m high and the angle of the hill is 45 degrees. The gift box falls down and   lands on a rein deer which is 1 m high standing on the ground. What is the spring compression?What’s the horizontal distance of the deer from the top of the hill?

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Asked Mar 28, 2019
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A 95 kg sled with a Xmas gift box of 5 kg pushed up horizontal surface together against a spring constant of 2000 N.  When the spring is released, the sled and the gift box together move along a horizontal surface and then keep moving on a ramp with friction. The ramp is 5m high (measured in vertical distance) and the coefficient friction is 0.2.

When the sled and the gift box reach up to the top of the ramp, the sled get stuck and gits box fly up in the air an additional 10 m high and the angle of the hill is 45 degrees. The gift box falls down and   lands on a rein deer which is 1 m high standing on the ground.

 

What is the spring compression?

What’s the horizontal distance of the deer from the top of the hill?

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Expert Answer

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Step 1

Sled and Xmas gift travel together on the path “ABCDEF”. At Point “A” spring is compressed and at point “B” spring is relaxed. Path “CD” has frictional surface and at point “D” gift detach from the sled to starts its projectile motion. Point “E” is the maximum height of projectile and at point “F” gift lands on a reindeer.

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Step 2

Given,

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Step 3

When spring released fully, Potential Energy in t...

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