A bolted lap joint is shown in the figure below. The bolts are 20 mm in diameter in 23 mm holes. The plates are 12 mm thick.X1 = 33 mm, X2 = 76 mm, and x3 = 50 mm.Allowable stresses of plates:• Tension in gross area = 0.60 Fy• Tension in net area = 0.50 Fu• Shear on net area = 0.30 Fu- Yield strength of plate, Fy 248 MPa• Ultimate tensile strength of plate, Fu = 400 MPaEx.toX2O O. Find the safe load P based on gross area yielding in kN.[ Select][Select]430489450[Sele None of the choices521[ Select]•Find the safe load P based on net area rapture in kN. L Select][ Select](Se 439468None of the choices512487[ Select]621530578None of the choices486Find the safe load P based on block shear in kN. [Select]<>Va

There are two types of forces that are acting on a circular surface. One type of force is Radial…

A bolted lap joint is shown in the figure below. The bolts are 20 mm in diameter in 23 mm holes. The plates are 12 mm thick. X1 = 33 mm, X2 = 76 mm, and x3 = 50 mm. - Allowable stresses of plates: • Tension in gross area = 0.60 Fy o Tension in net area = 0.50 Fu • Shear on net area = 0.30 Fu - Yield strength of plate, Fy = 248 MPa • Ultimate tensile strength of plate, Fu = 400 MPa • Find the safe load P based on gross area yielding in kN. [ Select ] [Select ] 430 489 450 [ Selee None of the choices 521 [ Select ] Find the safe load P based on net area rapture in kN. [ Select ] [Select] [S 439 468 None of the choices 512 487 [ Select] 621 530 578 None of the choices 486 • Find the safe load P based on block shear in kN. [ Select ]

A bolted lap joint is shown in the figure below. The bolts are 20 mm in diameter in 23 mm holes. The plates are 12 mm thick. X1 = 33 mm, X2 = 76 mm, and x3 = 50 mm. - Allowable stresses of plates: • Tension in gross area = 0.60 Fy o Tension in net area = 0.50 Fu • Shear on net area = 0.30 Fu - Yield strength of plate, Fy = 248 MPa • Ultimate tensile strength of plate, Fu = 400 MPa • Find the safe load P based on gross area yielding in kN. [ Select ] [Select ] 430 489 450 [ Selee None of the choices 521 [ Select ] Find the safe load P based on net area rapture in kN. [ Select ] [Select] [S 439 468 None of the choices 512 487 [ Select] 621 530 578 None of the choices 486 • Find the safe load P based on block shear in kN. [ Select ]

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)

Section: Chapter Questions

Problem 8.2.12P: Solve the preceding problem if the diameter is 480 mm, the pressure is 20 MPa, the yield stress in...

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Solve the preceding problem if the diameter is 480 mm, the pressure is 20 MPa, the yield stress in tension is 975 MPa, the yield stress in shear is 460 MPa, the factor of safety is 2,75, the modulus of elasticity is 210 GPa, Poissorfs ratio is 0.28, and the normal strain must not exceed 1190 x 10" . For part (b), assume that the tank thickness is 8 mm and the measured normal strain is 990 x 10~ .
Two steel tubes are joined at B by four pins (dp= 11 mm), as shown in the cross section a—a in the fiaure. The outer diameters of the tubes are dAB= 41 mm and dBC= 28 mm. The wall thickness are tAB= 6.5 mm and tBC= 7.5 mm. The yield stress in tension for the steel is sy = 200 MPa and the ultimate stress in tension is ??U:= 340 MPa. The corresponding yield and ultimate values in shear for the pm are 80 MPa and 140 MPa, respectively. Finally, the yield and ultimate values in bearing R between the pins and the tubes are 260 MPa, and 450 MPa, respectively. Assume that the factors safety with respect to yield stress and ultimate stress are 3.5 and 4.5. respectively. (a) Calculate the allowable tensile force P allowconsidering tension in the tube (b) Recompute P allowfor shear in the pins.(c)Finaly, recomputed Pallowfor bearing between the pm and the tubes. Which is the tubes. Which is the controlling value value of P?
A hollow circular tube T of a length L = 15 in. is uniformly compressed by a force P acting through a rigid plate (see figure). The outside and inside diameters of the tube are 3.0 and 2.75 in., respectively. A concentric solid circular bar B of 1.5 in. diameter is mounted inside the lube. When no load is present, there is a clearance c = 0.0I0 in. between the bar B and the rigid plate. Both bar and tube are made of steel having an c[autoplastic stress-strain diagram with E = 29 X LO3 ksi and err= 36 ksi. (a) Determine the yield load Pt- and the corresponding shortening 3yof the lube. (b) Determine the plastic load Ppand the corresponding shortening Spof the tube. (c) Construct a load-displacement diagram showing the load Pas ordinate and the shortening 5 of the tube as abscissa. Hint: The load-displacement diagram is not a single straight line in the region 0 ^ P ^ Pr
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