A molecular compound (Pt(NH3)2Cl2), is prepared by the following reaction K2PtCl4 + 2NH3 2KCl + Pt(NH3)2Cl2 How many grams of Pt(NH3)2Cl2 are formed from 111.66 g of K2PtCl4 and 2.285g of NH3 if the reaction takes place in 95% yield based on the reactant that is completely consumed. Atomic masses H = 1.0079 N = 14.0067 , K = 39.0983 Cl= 35.4527 and Pt= 195.08
A molecular compound (Pt(NH3)2Cl2), is prepared by the following reaction K2PtCl4 + 2NH3 2KCl + Pt(NH3)2Cl2 How many grams of Pt(NH3)2Cl2 are formed from 111.66 g of K2PtCl4 and 2.285g of NH3 if the reaction takes place in 95% yield based on the reactant that is completely consumed. Atomic masses H = 1.0079 N = 14.0067 , K = 39.0983 Cl= 35.4527 and Pt= 195.08
Chapter3: Stoichiometry
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A molecular compound (Pt(NH3)2Cl2), is prepared by the following reaction
K2PtCl4 + 2NH3 2KCl + Pt(NH3)2Cl2
How many grams of Pt(NH3)2Cl2 are formed from 111.66 g of K2PtCl4 and 2.285g of NH3
if the reaction takes place in 95% yield based on the reactant that is completely
consumed.
Atomic masses H = 1.0079 N = 14.0067 , K = 39.0983 Cl= 35.4527 and Pt= 195.08
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