A reaction has a standard free-energy change of –12.30 kJ mol-(-2,940 kcal mol-1). Calculate the equilibrium constant for the reaction at 25 °C.

Q: For the reaction NH,NO3(aq)N20(g) + 2H2O(1) AH° = -149.6 kJ and AS° = 99.9 J/K The equilibrium…

A: According to Gibbs Equation ∆G° = ∆H° - T∆S° And also ∆G° =-RTlnKeqm Thus we calculate equilibrium…

Q: At 355 K, AG = -5.7 kJ/mol for the reaction A (g) → 2 B (g). If the partial pressures of A and B are…

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Q: For the reaction CO(g) + 3H2(g)- →CH¼(g)+ H2O(g) AH° = -206.1 kJ and AS° = -214.7 J/K The…

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Q: Calculate the standard free-energy change and the equilibrium constant Kp for the following reaction…

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Q: For the reaction 2H,02)2H,0(1) + O2(g) AH° = -196.0 kJ and AS° = 125.7 J/K The equilibrium constant…

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Q: 2. Find the value for the equilibrium constant, K, at 25 °C (298 K) for the following reaction. The…

A: Given that -               Temperature =298K       Free energy (∆G°)= -13.6 kJ…

Q: Calculate the equilibrium constant at 37°C for the reaction Glucose + 60, + 36ADP + 36Phosphaten…

A: ∆G˚ = -423 kcal/mol At equilibrium, ∆G = 0. Conversion of temperature from ˚C to K:

Q: For the reaction N2(g) + O2(g)2NO(g) AH° = 180.6 kJ and AS° = 24.9 J/K The equilibrium constant for…

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Q: e standard free energy of formation of nitric oxide, NO, at 10 perature in an automobile engine…

A: □G° = 77.5 kJ/mol   = 77500 J/mol The relationship between Gibbs free energy and equilibrium…

Q: Consider the reaction H2(g) + C2H4(g)C2H6(g) Using the standard thermodynamic data in the tables…

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Q: Differentiate between Emf, Free Energy, and the Equilibrium Constant?

A: An electrochemical cell is a device which generated electricity by the virtue of flow of electrons…

Q: For the reaction2N2(g) + O2(g)2N2O(g)H° = 164.2 kJ and S° = -148.5 J/KThe equilibrium constant for…

A: The equilibrium constant can be calculated as per the following equation,

Q: Consider the following reaction:  Ni(s) + 4CO(g) <-->Ni(CO)4(g) The standard free energy of…

A: Given, ∆G0f for CO (g) = -137.3 kJ/mol ∆G0f for Ni (CO)4 (g) = - 587.4 kJ/mol ∆G0f for Ni (s) = 0

Q: Determine standard free energy change for the reaction:        NO2- (aq) + H2O (l) ------  HNO2…

A: The reaction taking place is given as, => NO2- (aq) + H2O (l) --------> HNO2 (aq) + OH- (aq)…

Q: Determine the equilibrium constant for the following reaction at 298 K.               SO3(g) +…

A: Given reaction:

Q: Chemistry At 355 K, AG = -5.7 kJ/mol for the reaction A %3D (g) → 2 B (g). If the partial pressures…

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Q: For the reaction H2(g) + C2H4(g)----->C2H6(g) H° = -137.0 kJ and S° = -120.7 J/K The equilibrium…

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Q: A reaction has a standard free‑energy change of −15.00 kJ mol−1(−3.585 kcal mol−1).Calculate the…

A: We know that, the Gibbs free energy of the reaction is related to the equilibrium constant as,…

Q: The standard free-energy change for the Haber process at 25 °C was obtained :N2(g) + 3 H2(g)⇌ 2…

A: Here, the relation between standard gibbs free energy and equilibrium constant:

Q: Write the equilibrium-constantexpression and calculate the value of the equilibrium constant and the…

A: The formula to calculate the ΔG°f  is shown below.

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction at 30.0 °C is – 147. kJ.…

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Q: 10) Consider the following reaction HCN (g) +2 H: (g) → CH:NH: (g) AH°= -158.0 kJ; AS°= -219.9 J/K…

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Q: 6) Determine the equilibrium constant for the following reaction at 298 K. SO3(g) + H20(g) –…

A: SO3(g) + H2O(g) ------> H2SO4(l) Given, Temperature = 298 K ∆G° = -90.5kJ Formula, ∆G = ∆G° +…

Q: 0. When potassium is added to water, the following reaction takes place readily. ArH° < 0 K(s) +…

A: Spontaneity of a process can depend on the temperature.  When a process occurs at constant…

Q: Van't Hoff studied the temperature dependence of the equilibrium constant, K, using two expressions…

A: The relationship given is, Given: At 0.00 oC or 273.15 K, the value of K = 0.000550  And at 100.0…

Q: Calculate the Equillibrium constant at 25 Degrees Celsius for the following Reaction: From the data…

A: We have to find equilibrium constant from the given data. Temperature = 25°C or 298 K

Q: Calculate ∆Gº and K for the equilibrium reaction at 25ºC O2 (g) + H2 (g) ⇌ H2O(g)

A: We know that, ∆Gº of O2 (g) = 0 kJ/mol ∆Gº of H2 (g) = 0 kJ/mol ∆Gº of H2O(g) = -228.6 kJ/mol

Q: The following data were collected for the reaction, H2(g)+I2(g)⇌2HI(g), at equilibrium at 25°C.…

A: Given Equilibrium Concentrations [H2]=0.10 mol L^-1 , [I2]=0.20 mol L^-1, [HI]=4.0 mol L^-1

Q: Calculate the equilibrium constant for the following reaction at 25o C, given that change in…

A: Given:The free energy change is 163.4 kJ/mol.Temperature = 250C = 25 + 273 K = 298 K.

Q: How does the value of ∆G° for a reaction relate to the equilib-rium constant for the reaction? What…

A: Relationship between standard Free energy ∆G° and the equilibrium constant is as follows: ∆G = ∆G°…

Q: Calculate the value of the thermodynamic equilibrium constant K.

A: The equilibrium constant can be written as the ratio of concentration of products to the…

Q: Standard Gibbs free energy of reaction 0 no preference for reactants or products at equilibrium…

A: Gibbs free energy is a thermodynamic quantity which is used to measure the capacity of system to do…

Q: The value of ΔG° (kJ/mol) at 25 °C is  -20.5. What is the equilibrium constant for this reaction at…

A: If the two opposing process in a reversible change are chemical change and the state in this change…

Q: Calculate the standard Gibbs free energy of the reaction, ΔG∘rxn. The standard enthalpy of the…

A: We have given that ∆G° of C2H4(g) = 68.4 KJ/mol ∆G° of H2O(l) = -237.1KJ/mol ∆G° of C2H5OH(l) =…

Q: At 1500°C the equilibrium constant for the reaction                                            CO(g)…

A: To determine the standard gibbs free energy, we need an equation that would relate chemical…

Q: Explain how a reaction that is not spontaneous may be driven forward by coupling it to a spontaneous…

A: A reaction that is capable of carrying a reaction in forward direction without any use of external…

Q: A reaction has a standard free-energy change of -13.20 kJ mol-(-3.155 kcal mol-). Calculate the…

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Q: For the reaction 2NO(g) + O2(g)2NO2(g) H° = -114.2 kJ and S° = -146.5 J/K The equilibrium…

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Q: Calculate the standard change in Gibbs free energy, AGxn, for the given reaction at 25.0 °C. KCI(s)…

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Q: A reaction has a standard free‑energy change of −18.20 kJ (−4.350 kcal mol−1). Calculate the…

A: Given, Standard free energy change, △Go = −18.20 kJ mol-1 = 18200 J mol-1    (1 kJ = 1000 J)…

Q: determine the equilibrium constant

A: ∆G° = -RTlnK  R is gas constant (8.314 j/k-mol)  T is the temperature in kelvin  K is the…

Q: For the reaction NH,CI(aq)NH3(g) + HCI(aq) AH° = 86.4 kJ and AS° = 79.1 J/K The equilibrium constant…

A: The reaction given is, =&gt; NH4C (aq) --------&gt; NH3 (g) + HCl (aq) Given : ΔHo = 86.4 KJ = 86400…

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction at 25.0 °C is 95.6 kJ.…

A: we have given that  ∆G = 95.6KJ Temperature = T = 25°C=  298.15K To calculate equilibrium constant K…

Q: Find the standard enthalpy of a reaction for which the equilibrium constant is (a) doubled, (b)…

A: First we have to find out standard enthalpy of a reaction.

Q: For the reaction CO(g) + 3H2(g)→CH4(g) + H,O(g) AH° = -206.1 kJ and AS° = -214.7 J/K The equilibrium…

A: Given T = 290.0 K, ∆H° = -206.1 kJ;  ∆S° = -214.7 J/K Equilibrium constant, K = ?

Q: Consider the reaction at 25°C, where CaCO3(s) decomposes to form CO2(g) + CaO(s) If the standard…

A: Standard Gibbs free energy change of a reaction is calculated from the standard enthalpy and entropy…

Q: For the reaction CH4(g) + H2O(g)------>3H2(g) + CO(g) H° = 206.1 kJ and S° = 214.7 J/K The…

A: The balanced reaction taking place is given as, =&gt; CH4 (g) + H2O (g) -------&gt; 3 H2 (g) + CO…

Q: The standard free energy of formation of gaseous hydrogen iodide is 1.30 kJ/mol at 25°C. What is KP…

A: The relation between standard free energy change and equilibrium constant is given as :

Q: - Calculate the equilibrium constant given that the standard Gibbs free energy of reaction is -8.16…

A: Given :-  ∆G° = -8.16 kJ/mol  T = 249 K  To calculate :-  K (equilibrium constant)