a) Show the mechanism of synthesis of an amide from an ester and a primary amine: b) The ester responsible for the aroma of the rum has the following structural formula: CH3 H-C-CH2-0-C-CH3 CH3
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- For the following reaction between an amine and an anhydride, which is the correct collection of 3 products fromed? The correct answer is A but please explain:)Please complete the following question. There is no need to provide an explaination. 20Give a clear explanation handwritten answer...complete the following reaction
- Identify the organic functional groups and reaction type for the following reaction.Please include everything including the letter and the answers.The reactant is a(n)a. amideb. aldehydec. alcohold. carboxylic acide. esterf. ketoneThe product is a(n)a. carboxlyate ionb. ammonium ionc. alcohold. carboxylic acide. ketonef. aldehydeThe reaction type isa. hydrationb. esterificationc. hydrolysis (in acid)d. hydrolysis (in base)e. amide synthesisf. amide synthesisg. dehydrationh. acid baseNitriles are reduced to primary amines when reacting with lithium aluminum hydride (LiAlH4) followed by H2O. Using curved arrows, draw the mechanism for nitrile reduction with LiAlH4 for the reaction shown. Be sure to include lone pairs and charges where relevant.Checking my answer, there was difference with solution. (organic chemistry smith 5th ed 2.47P (d)) Solution said 'the acid base reaction between pentyne and ammonia is product way because pka of pentyne is 25, ammonia is 38 so pentyne will be deprotanted by ammonia.' but I think (and as written in the book) NH4+ is stronger acid than pentyne and acid-base reaction works when reactant is stronger acid than product conjugate acid. It isn't match that pentyne makes NH4+. who is incorrect?
- The question is: "Draw the curved arrow mechanism for the reaction between pentan-2-one and (CH3)3O– in t-butanol to form an enolate. Draw all electrons and charges on both resonance structures. Then answer the question about the reaction." I got the initial arrows correct, but am not entirely sure what the carbanion intermediate would look like and then what the curved arrows would be to convert it to its final oxanion formUsing the reaction shown in Box (the attack of an amine on the carbonyl group of a ketone) as a starting point, draw curved arrows to represent the base-catalyzed reaction (when the group —B: is present).A carboxylic acid reacts with water to form a carboxylate ion and H3O+ . Complete the reaction. Please help me figure out the answer for this reaction. First part only!