A simple pendulum consists of a 0.8-kg bob connected to a massless inextensible cord with a length L = 1.4 m. The bob is set into motion and its angular displacement is given by e(t) = 0.11cos(wt), where e is in radians andt is in seconds. Take g = 9.8

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Chapter6: Circular Motion And Other Applications Of Newton’s Laws
Section: Chapter Questions
Problem 6.8P: Consider a conical pendulum (Fig. P6.8) with a bob of mass m = 80.0 kg on a string of length L =...
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4:39
O 4 l 61% i
0.031 kg
0.047 kg
0.024 kg
A simple pendulum consists of a 0.8-kg bob
connected to a massless inextensible cord
with a length L = 1.4 m. The bob is set into
motion and its angular displacement is
given by 0(t) = 0.11cos(wt), where e is in
radians and t is in seconds. Take g = 9.8
m/s^2, determine the mechanical energy of
this pendulum.
0.052 J
0.046 J
0.090 J
0.066 J
0.085 J
A block of mass m = 5 Kg is attached to a
spring of spring constant k. The block
oscillates in simple harmonic motion on a
frictionless horizontal surface. The block-
spring total mechanical energy is 14.4 J. The
maximum velocity of block, vmax, is:
Transcribed Image Text:4:39 O 4 l 61% i 0.031 kg 0.047 kg 0.024 kg A simple pendulum consists of a 0.8-kg bob connected to a massless inextensible cord with a length L = 1.4 m. The bob is set into motion and its angular displacement is given by 0(t) = 0.11cos(wt), where e is in radians and t is in seconds. Take g = 9.8 m/s^2, determine the mechanical energy of this pendulum. 0.052 J 0.046 J 0.090 J 0.066 J 0.085 J A block of mass m = 5 Kg is attached to a spring of spring constant k. The block oscillates in simple harmonic motion on a frictionless horizontal surface. The block- spring total mechanical energy is 14.4 J. The maximum velocity of block, vmax, is:
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