Then we have:A simple pendulum is made of a 2 m-string and a bob of mass m. At t = 0, thependulum is at its equilibrium position and is given an initial velocity v =The maximum angular speed, O'max, is:0.2 m/s.0.1 rad/s0.4 rad/s0.05 rad/s0.8 rad/s0.2 rad/sA musical note on a piano has a frequency of 40 Hz. If the tension in the 2-mstring is 308 N, and one-half wavelength occupies the string, what is the mass ofwire?

Answered: Image /qna-images/answer/b498d7f6-7013-4e02-a7b3-19bfa1486aae.jpg

A simple pendulum is made of a 2 m-string and a bob of mass m. At t = 0, the pendulum is at its equilibrium position and is given an initial velocity v = 0.2 m/s. The maximum angular speed, e'max, is: O 0.1 rad/s O 0.4 rad/s 0.05 rad/s O 0.8 rad/s O 0.2 rad/s

A simple pendulum is made of a 2 m-string and a bob of mass m. At t = 0, the pendulum is at its equilibrium position and is given an initial velocity v = 0.2 m/s. The maximum angular speed, e'max, is: O 0.1 rad/s O 0.4 rad/s 0.05 rad/s O 0.8 rad/s O 0.2 rad/s

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter12: Oscillatory Motion

Section: Chapter Questions

Problem 13CQ: Consider the simplified single-piston engine in Figure CQ12.13. Assuming the wheel rotates with...

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We do not need the analogy in Equation 16.30 to write expressions for the translational displacement of a pendulum bob along the circular arc s(t), translational speed v(t), and translational acceleration a(t). Show that they are given by s(t) = smax cos (smpt + ) v(t) = vmax sin (smpt + ) a(t) = amax cos(smpt + ) respectively, where smax = max with being the length of the pendulum, vmax = smax smp, and amax = smax smp2.
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