A spring is stretched 200 mm by a 15-kg block. If the block is displaced 200 mm downward from its equilibrium position and given a downward velocity of 0.75 m/s, determine the equation which describes the motion. Assume that positive displacement is downward.

Principles of Physics: A Calculus-Based Text
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Chapter12: Oscillatory Motion
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SUBJ.:DYNAMICS OF RIGID BODIES
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A spring is stretched 200 mm by a 15-kg block. If the block is displaced 200 mm downward from
its equilibrium position and given a downward velocity of 0.75 m/s, determine the equation
which describes the motion. Assume that positive displacement is downward.
y = 0.107 sin (7.00t) + 0.1 cos (7.00t)
y = -0.25 sin (7.00t) + 0.107 cos (7.00t)
y = 0.17 sin (7.00t) - 0.17 cos (7.00t)
y = 0.1 sin (7.00t) + 0.2 cos (7.00t)
O y = 0.71 sin (7.00t) + 0.12 cos (7.00t)
O y = 0.107 sin (7.00t) + 0.2 cos (7.00t)
Transcribed Image Text:A spring is stretched 200 mm by a 15-kg block. If the block is displaced 200 mm downward from its equilibrium position and given a downward velocity of 0.75 m/s, determine the equation which describes the motion. Assume that positive displacement is downward. y = 0.107 sin (7.00t) + 0.1 cos (7.00t) y = -0.25 sin (7.00t) + 0.107 cos (7.00t) y = 0.17 sin (7.00t) - 0.17 cos (7.00t) y = 0.1 sin (7.00t) + 0.2 cos (7.00t) O y = 0.71 sin (7.00t) + 0.12 cos (7.00t) O y = 0.107 sin (7.00t) + 0.2 cos (7.00t)
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