A student determines that an aqueous solution that contains 0.155 M potassium acetate and 0.344 M acetic acid, also has a H3O* concentration of 5.67×105 M. Based on these data, calculate the value of the equilibrium constant K for the equilibrium: CH3COOH(aq) +H2O=H30*(aq) + CH3COO"(aq) (1) as is usually done, without the inclusion of water in the expression for K: K= (2) for comparison, with the inclusion of water in the expression for K: K=

Chemistry for Engineering Students
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Author:Lawrence S. Brown, Tom Holme
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.41PAE: Because calcium carbonate is a sink for CO32- in a lake, the student in Exercise 12.39 decides to go...
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A student determines that an aqueous solution that contains 0.155 M potassium acetate and 0.344 M acetic acid, also has a H30* concentration of 5.67x10 M.
Based on these data, calculate the value of the equilibrium constant K for the equilibrium:
CH3COOH(aq) +H2O=H30*(aq) + CH3COO (aq)
(1) as is usually done, without the inclusion of water in the expression for K: K=
(2) for comparison, with the inclusion of water in the expression for K: K=
Transcribed Image Text:A student determines that an aqueous solution that contains 0.155 M potassium acetate and 0.344 M acetic acid, also has a H30* concentration of 5.67x10 M. Based on these data, calculate the value of the equilibrium constant K for the equilibrium: CH3COOH(aq) +H2O=H30*(aq) + CH3COO (aq) (1) as is usually done, without the inclusion of water in the expression for K: K= (2) for comparison, with the inclusion of water in the expression for K: K=
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