A study of SNPs associated with familial hypercholesterolemia has revealed that 7 or more contributing alleles at 6 loci can lead to elevated levels of cholesterol in the blood. What is the probability that the following parents, AaBbccDDeeFF x AAbbCCDdEeFF, will have children that are susceptible to hypercholesterolemia?

A study of SNPs associated with familial hypercholesterolemia has revealed that 7 or more contributing alleles at 6 loci can lead to elevated levels of cholesterol in the blood. What is the probability that the following parents, AaBbccDDeeFF x AAbbCCDdEeFF, will have children that are susceptible to hypercholesterolemia?

Name: A study of SNPs associated with familial hypercholesterolemia has reve
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Description: A study of SNPs associated with familial hypercholesterolemia has revealed that 7 or more contributing alleles at 6 loci can lead to elevated levels of cholesterol in the blood. What is the probability that the following parents, AaBbccDDeeFF x AAbbC

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter5: The Inheritance Of Complex Traits

Section: Chapter Questions

Problem 5QP: As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women....

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In humans, a very rare dominant allele that causes the little fingerto be crooked has a penetrance of 80%. In other words, 80% of heterozygotes carrying the allele will have a crooked little finger. If ahomozygous unaffected person has children with a heterozygotecarrying this mutant allele, what is the probability that an offspring will have a little finger that is crooked?
In pedigrees, individuals are usually specified by using a Roman numeral for their generation in the chart and an Arabic number for their position (reading left to right) within that generation. If we use the letter c for the allele that causes cystic fibrosis, what are the genotypes of individuals III-3 and III-4 (the third and fourth individuals shown in generation III) in the pedigree that shows this disease?
Farmer Brown had two hogs, Olga and Hank. Olga and Hank were normal, healthy hogs, but whenever Farmer Brown crossed them, a few of the piglets had cleft palates. Assuming a simple autosomal basis for cleft palate, what are the genotypes of Olga and Hank, and about what proportion of the piglets are born with a cleft palate?
Achondroplasia is a hereditary condition caused by a dominant allele in humans (dominant allele A). This disorder affects bone growth specifically in long bones of the upper and lower limbs by preventing the ossification of bones from cartilage. Determine the genotypes of the parents and offspring for the following family scenarios in a and b below. Two parents who have the Achondroplasia phenotype have 4 children where 1 is normal NOTE: You must draw a Punnet square to determine the possible genotypes of te children. When two alternative genotypes are possible for an individual, indicate both.
In humans, the genetic disease cystic fibrosis is caused by a recessive allele (a). The normal (healthy) allele is dominant (A). What is the genotype of someone who has cystic fibrosis? What are the two different genotypes that a healthy person could have? If two people were both heterozygous for the cystic fibrosis gene, what fraction of their children would be likely to have this disease? Hint: Draw a Punnett square to figure it out.
Phenylketonuria (PKU) is an inherited disease caused by a recessive allele. Individuals with PKU have two recessive alleles and have very low levels of an enzyme that is needed to properly break down proteins. If a woman and her husband are both carriers and have three children, what is the probability of each of the following? Show your math. (Hint: You can represent your probabilities as fractions or decimals, but probabilities are always between 0 and 1) a. All three children are of normal phenotype. b. One or more of the three children have the disease. c.All three children have the disease.
Within a mouse population, the black fur allele (B) is dominant to the white fur allele (b) and the short whisker allele (S) is dominant to the long-whisker allele (s). A heterozygous black-furred short-whiskered mouse is crossed with a homozygous white-furred long-whiskered mouse. What percentage of the offspring will be black-furred with long whiskers?
Given the pedigree for the trait A (with alleles A and a following mendelian genetics) below: What is the genotype of invididual I-1?
As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women. During his tenure as guard, he had numerous clandestine affairs. In each case, children resulted. Subsequently, some of the childrenwho had no way of knowing that they were relatedmarried and had children of their own. Assume that two pairs of genes determine height. The genotype of the 7-foot-tall Potsdam Guard was A9A9B9B9, and the genotype of all of his 5-foot clandestine lovers was AABB. An A9 or B9 allele in the offspring each adds 6 inches to the base height of 5 feet conferred by the AABB genotype. a. What were the genotypes and phenotypes of all the F1 children? b. Diagram the cross between the F1 offspring, and give all possible genotypes and phenotypes of the F2 progeny
The following pedigree shows the pattern of inheritance of red-green color blindness in a family. Females are shown as circles and males as squares; the squares or circles of individuals affected by the trait are filled in black. What is the chance that a son of the third-generation female indicated by the arrow will be color blind if the father is not color blind? If he is color blind?
Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?
Why are monozygotic twins who are reared apart so useful in the calculation of heritability?