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A. Balance the following equation by oxidation number method: a. Cu + HNO, b. HCIO, + H,S ► S, + HCl c. FESO, + K,Cr,O,+ H,SO, d. MnSO, + PbО, + H,SO, NO + Cu(NO,)2 + Н.О + H,0 8. >K,SO, + Cr,(SO,);+Fe,(SO,), + H,O » HMNO, + PbSO, + H,0 4 4 4 B. For each redox reaction, idențify the oxidizing and reducing agents.

A. Balance the following equation by oxidation number method: a. Cu + HNO, b. HCIO, + H,S ► S, + HCl c. FESO, + K,Cr,O,+ H,SO, d. MnSO, + PbО, + H,SO, NO + Cu(NO,)2 + Н.О + H,0 8. >K,SO, + Cr,(SO,);+Fe,(SO,), + H,O » HMNO, + PbSO, + H,0 4 4 4 B. For each redox reaction, idențify the oxidizing and reducing agents.

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.121QP: A constant current of 1.40 amp is passed through an electrolytic cell containing a 0.100 M solution...
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a. Cu + HNO, b. HСIO, + H,S A. Balance the following equation by oxidation number method: NO + Cu(NO,)2 + H,O + HCl S. c. FESO, + K,Cr,O,+ H,SO,→K,SO, + Cr,(SO,);+Fe,(SO,), + H,O → HMNO, + Н,О 4 4/3 d. MnSO, + PЬ0, + H,SO, + PЬSО, + H,О 4 B. For each redox reaction, idențify the oxidizing and reducing agents.
Transcribed Image Text:a. Cu + HNO, b. HСIO, + H,S A. Balance the following equation by oxidation number method: NO + Cu(NO,)2 + H,O + HCl S. c. FESO, + K,Cr,O,+ H,SO,→K,SO, + Cr,(SO,);+Fe,(SO,), + H,O → HMNO, + Н,О 4 4/3 d. MnSO, + PЬ0, + H,SO, + PЬSО, + H,О 4 B. For each redox reaction, idențify the oxidizing and reducing agents.
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