Active Dosage Form Raw Materials Actual Yield Formulation Packaging Ingredient 3 kgs. p-aminophenol and 2 kgs. acetic anhydride 2.6 kgs paracetamol 500 mg per tablet 20 tablets per blister pack Paracetamol Tablet Balanced Chemical Reaction % composition by mass of each compound Mass to Mass Stoichiometry Calculation Limiting Reagent Excess Reagent Amount (g) in excess % Yield Number of dosage form and packaging that can be produced from stoichiometric calculation

Active Dosage Form Raw Materials Actual Yield Formulation Packaging Ingredient 3 kgs. p-aminophenol and 2 kgs. acetic anhydride 2.6 kgs paracetamol 500 mg per tablet 20 tablets per blister pack Paracetamol Tablet Balanced Chemical Reaction % composition by mass of each compound Mass to Mass Stoichiometry Calculation Limiting Reagent Excess Reagent Amount (g) in excess % Yield Number of dosage form and packaging that can be produced from stoichiometric calculation

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter9: Chemical Quantities

Section: Chapter Questions

Problem 100CP: he production capacity for acrylonitrile (C3H3N)in the United States is over 2 billion pounds per...

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Given Active Ingredient: precipitated sulfur (ointment) Raw Materials: 500 g calcium polysulphide and 1.5 kg hydrochloric acid Actual Yield: 343.4g precipitated sulfur Formulation: 250 mg per jar Dosage form: Ointment packaging:100 jars per box Synthesis and Packaging (Need answer)- Balanced Chemical Equation:- % composition by mass of each compound:- Mass to Mass Stoichiometry Calculation:- Limiting Reagent:- Excess Reagent:- Amount (g) in excess: % Yield:- Number of dosage form and packaging that can be produced from stoichiometric solution:
GivenRaw Materials: 500 g calcium polysulphide and 1.5 kg hydrochloric acid Actual Yield: 343.4g precipitated sulfurFormulation: 250 mg per jarDosage form: Ointment Packaging: 100 jars per boxWhereas the balanced chemical reaction, as given in the problem is: CaS5+2HCl => 4S + CaCl2 + H2SMy problem: Find the number of dosage form and packaging that can be produced from the stoichiometric calculation based on the result upon finding the Mass to Mass Stoichiometry Calculation. I have based my answer to the mass stoichiometry from this link: https://www.bartleby.com/questions-and-answers/given-raw-materials-500-g-calcium-polysulphide-and-1.5-kg-hydrochloric-acid-actual-yield-343.4g-prec/b1de1102-f27f-4c8d-9b4e-c7fe8e6104b6Thanks, by the way. But can you still help me find the number of dosage from and packaging?
Sample: Saline 0.900% (m/v), in sodium chloride (NaCl). Data: M.A. (g/mol): Na = 22.9898; K = 39.0983; Cr=51.9961; Ag = 107.8682; Cl = 35.453; N=14.0067; O = 15.9994. Material available in the laboratory's warehouse: Reagents: distilled water; standardized solution of silver nitrate (AgNO₃), at a concentration of 0.09980 mols/L; Potassium chromate solution (K₂CrO₄) 1%; ammoniacal ferric alum solution [Fe(NH₄)(SO₄)₂] and; nitrobenzene (or cooking oil, alternatively); 0.1000 mols/L potassium thiocyanate (KSCN) standard solution. Glassware: beakers of all sizes available on the market; 50, 100, 150, 200 and 250 ml Erlenmeyers; 10.00 and 25.00 mL volumetric pipettes; 15.00 mL burette; 30.00, 50.00 and 100.00 mL volumetric flasks Calculate the molarity of saline, in terms of the NaCl concentration (concentration in mols/L). (a) 0.900 mols/L (b) 5.84 mols/L (c) 0.154 mols/L (d) 0.0154 mols/L
To prepare a very dilute solution of K2Cr2O7 (294.18 g/mol), 0.661 g of K2Cr2O7 was transferred to a 250.0-mL volumetric flask and adding water to the mark. A sample of this solution of volume 1.000 mL was then transferred to a 500.0-mL volumetric flask and diluted to the mark with water. Subsequently, 10.0 mL of the diluted solution was transferred to a 250.0-mL flask and diluted to the mark with water. What is the final concentration of K2Cr2O7 in this last solution?
A 290.3-g sample of ground water is analyzed for calcium. The Ca2+ in the sample is first precipitated and filtered-off as NH4CaPO4·7H2O. This precipitate is dried and heated, releasing water and ammonia to yield anhydrous calcium pyrophosphate (Ca2P2O7). The mass of Ca2P2O7 obtained is 0.0534 g.Give the calcium content of the ground water in parts per million
In an experiment, a hydrated CuSO4 salt was heated and thusdehydrated. Determine the % H2O by weight in the hydrated CuSO4 salt.mass of empty dish 43.571 gmass of dish + hydrated salt 44.326 gmass of dish + dehydrated salt 44.054 g
For the preparation of Aspirin calculate limiting factor, theoretical yield calculations, percent yield calculations for salicylic acid used 8.6g, Acetic anhydride used 3.9ml, Phosphoric acid used 0.25ml and Acetyl salicylic acid obtained 7.2g
In the standardization of HCl using pure anhydrous sodium carbonate as the primarystandard for methyl orange as an indicator, 1.0 mL HCl was found to be equivalent to 0.05gof sodium carbonate (MW =106). The normality of HCl is:
The concentration of arsenic in an insecticide can be analyzed gravimetrically by precipitating it as MgNH4AsO4. The precipitate is ignited and weighed as Mg2As2O7. Calculate the %w/w As2O3 in a 2.025-g sample of insecticide that yields 207.5 mg of Mg2As2O7
The concentration of arsenic in an insecticide can be determined gravimetrically by precipitating it as MgNH4AsO4. The precipitate is ignited and weighed as Mg2As2O7. Determine the %w/w As2O3 in a 1.627-g sample of insecticide that yields 106.5 mg of Mg2As2O7.
Complete and balance ---Co2(CO3)3(s)+heat---> ---H2O(l)+---As2O5(s)---> ---NaClO3(s)+heat---> ---Mg(s)+---H2SO4(aq)--->
What Is the mass to mass stoichiometry calculation in this balanced chemical equation? (Given that the sulfur in the yield is octasulfur since this is a precipitated sulfur) 8CaS5 + 16HCl → 5S8 + 8CaCl2 + 8H2 and what is the A.) limiting reagent b.) excessive reagent given the mass attached in the photo?