Calculate the limiting and excess reagents in GRAMS of Boric acid using the given. Note: use MASS TO MASS Stoichiometry calculations/formula. Active Ingredient Raw Materials Actual Yield Formulation Dosage Form Packaging Boric acid 3 kgs. sodium borate and 1.5 kg hydrochloric acid 1.5 kgs boric acid 0.004 mg per 50 microliter drop Ophthalmic solution 30 mL of plastic drip bottles

Q: Ingredient 2 kgs calcium oxide and 1.75 160mg per 10mL Calcium 1.75kgs carbonate calcium Sus kg H2O…

A: the CaCO3 is formed by the following reactions-CaO+H2O→CaOH2CaOH2+CO2→CaCO3+H2Othe given moles of…

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Q: athandler&extension_handler=extension_open_button&file=httpss dent Upgrade 0 9O Moodle…

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A: Given: mass of cream of tartar = 1.5 kg = 1500 g mass of sodium carbonate monohydrate = 2.5 kg =…

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Q: Active Raw Materials Actual Yield Formulation Dosage Form Packaging Ingredient Aspirin 2 kgs.…

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Q: HO, H2SO4 HO, Acetic Anhydride Acetylsalicylic Acid (Aspirin) Salicylic Acid Acetic Acid Acetic…

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Q: Formulatio Active Ingredient Actual Yield Dosage Form Packaging Raw Materials Seignette salt 1.5 kgs…

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Q: How many moles of MgO is produced from 0.200 g of Mg? 2Mg + O2 --> 2MgO. ( gram to mole conversion)…

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Q: mass of cuso4: 7.00g. mass of fe: 2.00g. mass of filter paper: 1.50g. mass of cu solid: 2.16g. mass…

A: Mass of Cu(s) = 2.16 g  Mass of CuSO4 = 7.00 g

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Q: i…

A: Given  moles of Sodium = 0.0850 moles

Q: How many g of ZnS is needed to react completely with 41.22 gram O2 according to this equation? 2ZnS…

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Q: Also please help me with Question 4.

A: 1) Given: %(w/w) of acetic acid = 5 % Density of vinegar = 1.05 g/mL. And volume of vinegar solution…

Q: Mass of the original sample of mixture (g) 1.547 Mass of recovered naphthalene (g) 0.511 Mass of…

A: Since you have asked multiple question,we will solve the first question for you.If you want any…

Q: Observation of product Flaky and light gray Solid Mass of product and crucible 31.970g Mass of…

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Q: Active Dosage Form Raw Materials Actual Yield Formulation Packaging Ingredient Calcium carbonate…

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Q: This is part of a continuing problem from the previous carbohydrate sample. Use that data to…

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Q: DCE Home Insert Draw Design Layout References Mailings Review Calibri (Bo... ✓12 A A Aa Po A✓ ✓ A А…

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Q: Determine the limiting reagent in the following balanced equation: HsS(g) + 2H2O(l) + 2HCl + 4I2(aq)…

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Q: Given: Active Ingredient: Potassium Nitrate Raw Materials: 3 kgs. acetic acid and 2.5 kgs. potassium…

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Q: Mass of weighing tray:  1.435 g Mass of weighing tray and salicylic acid:  3.469 g Mass of salicylic…

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Q: Active Raw Materials Actual Yield Formulation Dosage Form Packaging Ingredient 500 g calcium…

A: Given that -  Mass of precipitated Sulfur, S = 343.4 g  Mass of calcium polysulphide, CaS4 = 500 g…

Q: What is the : Mass to mass Stoichiometry Calculation, Limiting reagent, Excess Reagent,

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A: Active ingredient = Calcium carbonate, Raw material = 2 kg calcium oxide and 1.75 kg H2O Actual…

Q: How many g of ZnS is needed to react completely with 41.22 gram O2 according to this equation? 2ZnS…

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Q: Active Dosage Form Raw Materials Actual Yield Formulation Packaging Ingredient 3 kgs. p-aminophenol…

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Q: With a product weight of 3.77g .Use the limiting reagent to  Calculate the theoretical yield of…

A: % yield is defined as the (actual yield/Theoretical yield)*100   The percentage yield is 57.91%

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".