After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 55.0 cm . The explorer finds that the pendulum completes 109 full swing cycles in a time of 142 s .How does one determine the magnitude of the gravitational acceleration on this planet, expressed in meters per second?

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Asked Oct 20, 2019
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After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 55.0 cm . The explorer finds that the pendulum completes 109 full swing cycles in a time of 142 s .

How does one determine the magnitude of the gravitational acceleration on this planet, expressed in meters per second?

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Expert Answer

Step 1

Given

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Length of the pendulum 55 cm = 55x10 m total time Time period of the pendulum, T number of cycles 142 T 109 T 1.30 s

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Step 2

Time period

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T 27T I g 4 т?

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Step 3

Putting the v...

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55x10 g 4(3.14) (1.30) g 12.83 m/s2

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