age 2 Figure Q2 (b) Given : The allowable shear stress i: c) () s0 kPa Ic The tor sion formula :r = J I (0.019) A (0.019)^4 so x10': ; Therefore, the max torque T = 2 For noint king on the outside s uface of the shaft:

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter3: Torsion
Section: Chapter Questions
Problem 3.7.8P: A tubular shaft being designed for use on a construction site must transmit 120 kW at 1,75 Hz, The...
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age 2
Figure Q2 (b)
Given : The allowable shear stress i:
kPa
80
Q2 c) 0 The tor sion formula :=
J
I (0.019)
A (0.019)^4
Therefore, the max torque T =
Nm
80
x10
2.
Q2 c) (i)
For point lying on the outside suurface of the shaft:
x10° = (0.019)
I (0.019*-0.0125 *)
: Therefore, the max torque T
Nm
80
Q2 c) (iii) The shear stress at point located at inner surface of shaft,
kPa
T'c
A (c,* -c,
T'c
T= -=.
)(0.0125) =
7 (0.019*.0.0125)
Transcribed Image Text:age 2 Figure Q2 (b) Given : The allowable shear stress i: kPa 80 Q2 c) 0 The tor sion formula := J I (0.019) A (0.019)^4 Therefore, the max torque T = Nm 80 x10 2. Q2 c) (i) For point lying on the outside suurface of the shaft: x10° = (0.019) I (0.019*-0.0125 *) : Therefore, the max torque T Nm 80 Q2 c) (iii) The shear stress at point located at inner surface of shaft, kPa T'c A (c,* -c, T'c T= -=. )(0.0125) = 7 (0.019*.0.0125)
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