ALEKS - Ciaa Dorley- Learn www-aw..aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQs_dp5pR4ENzvdYC Apps M SIMnet - Assigne... E Login | Student Veri. Course Home B Logout OMEASUREMENT AND MATTER Predicting and naming ionic compounds formed by two eleme. Decide whether each pair of elements ih the table below will form an ionic compound. formed in the spaces provided. empirical formula of ionic compound Forms ionic compound? element #2 element #1 name of ionic compound cesium calcium yes no ou, barium chlorine yes nuo chlorine cesium yes ou. sulfur barium nu yes

ALEKS - Ciaa Dorley- Learn www-aw..aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQs_dp5pR4ENzvdYC Apps M SIMnet - Assigne... E Login | Student Veri. Course Home B Logout OMEASUREMENT AND MATTER Predicting and naming ionic compounds formed by two eleme. Decide whether each pair of elements ih the table below will form an ionic compound. formed in the spaces provided. empirical formula of ionic compound Forms ionic compound? element #2 element #1 name of ionic compound cesium calcium yes no ou, barium chlorine yes nuo chlorine cesium yes ou. sulfur barium nu yes

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Help with Part A B and C: Ksp Values: Ionic CompoundFormulaKsp Aluminum hydroxideAl(OH)31.8×10–5 Aluminum phosphateAlPO46.3×10–19 Barium carbonateBaCO35.1×10–9 Barium chromateBaCrO41.2×10–10 Barium fluorideBaF21.0×10–6 Barium hydroxideBa(OH)25×10–3 Barium sulfateBaSO41.1×10–10 Barium sulfiteBaSO38×10–7 Barium thiosulfateBaS2O31.6×10–6 Bismuthyl chlorideBiOCl1.8×10–31 Bismuthyl hydroxideBiOOH4×10–10 Cadmium carbonateCdCO35.2×10–12 Cadmium hydroxideCd(OH)22.5×10–14 Cadmium oxalateCdC2O41.5×10–8 Cadmium sulfide*CdS8×10–28 Calcium carbonateCaCO32.8×10–9 Calcium chromateCaCrO47.1×10–4 Calcium fluorideCaF25.3×10–9 Calcium hydrogen phosphateCaHPO41×10–7 Calcium hydroxideCa(OH)25.5×10–6 Calcium oxalateCaC2O42.7×10–9 Calcium phosphateCa3(PO4)22.0×10–29 Calcium sulfateCaSO49.1×10–6 Calcium sulfiteCaSO36.8×10–8 Chromium(II) hydroxideCr(OH)22×10–16 Chromium(III) hydroxideCr(OH)36.3×10–31 Cobalt(II) carbonateCoCO31.4×10–13 Cobalt(II) hydroxideCo(OH)21.6×10–15 Cobalt(III) hydroxideCo(OH)31.6×10–44…
Consi‎der follo‎wing rea‎ction: HgO (s) -> Hg(l) + ½ O2 (g) Delta H = +90.7 kj/mol. Wh‎at qua‎ntity of h‎eat in kj/mol is req‎uired to prod‎uce on‎e m‎ole HgO? Wri‎te your answer wit‎hout units. Gi‎ven the fol‎lowing data 2Cl‎F(g) + O‎2(g) --> Cl2‎O(g) + F2‎O (g) De‎lta H= 167.4 kJ I 2Cl‎F3(g) + 2O‎2(g) --> Cl‎2O(g) + 3F2‎ O (g) Delta H= 341.4 kJ II 2 ‎F2(g) + O‎2(g) ---> 2F2O‎ (g) Delt‎a H= -43.4 kJ III Calc‎ulate the de‎lta H in kJ for below‎ reaction: ClF(g) + F2(g) ---> ClF3(g)
1. Explain the step-by-step process of the solution. Make it as detailed as it can be. ENCODE THE ANSWER.
Please don't provide handwritten solution... It is saying this is incorrect, please help how is this incorrect? :)
How does Sb2(S O4)5(s) break up in solution? Write subscripts and superscripts as normal numbers and do not include spaces in your answer. Do not include states like (aq) or "1" in front of single atoms or charges. For example, the answer for NiCl3(s) would be Ni3++3Cl- For example, the answer for Sb3(PO4)5(s) would be 3Sb5++5PO43- Possibly relevant polyatomic ions: CN-,OH-, NO3-, NO2-, ClO3-, ClO4-, CO32-, SO42-, CrO42-, Cr2O72-, PO43-, PO33- Screen Reader User: For example, the answer for NiCl3(s) would be Ni3++3Cl minus For example, the answer for Sb3(P O4)5(s) would be 3Sb5++5PO43 minus Possibly relevant polyatomic ions: CN minus,O H minus, N O3 1 minus, N O2 1 minus, Cl O3 1 minus, Cl O4 1 minus, C O3 2 minus, S O4 2 minus, Cr O4 2 minus, Cr2 O7 2 minus, P O4 3 minus, P O3 3 minus
Write the ionic forms of the following elements and compute for the respective milliequivalent weight; 1.Iron= 57 g/mole; 2. Magnesium= 24 g/mole; 3. Potassium=39 g/mole; 4. Ammonium nitrogen= 15g/mole; and 5. Manganese = 54.9 g/mole. (PLEASE PROVIDE FULL SOLUTION)
Please just send paper solutions and it should looķ like the example
Don't give handwritten answers otherwise I will give you disli
The attractive force between two ions in Na20, Fc is 8.64x10-9N. What is the bond length a0 (in nm) given that valence of the charged Na+ is Z1=+1, for O-, is Z2 =-2, the charge of a single electron q is 0.16x10-18 C and the proportionality constant k0=9x109 V.m/C? Note that K=k0(Z1q)(Z2q) and that 1 V.C = 1 J.
please help me solve the rest of table Concentration of AR Stock Solution (ppmppm) 21.22 Unrounded Rounded Concentration of AR Stock Solution (μMμM) 42.7461 42.7
Sketch a qualitative enthalpy diagram for the process of dis-solving NaI(s) in H₂O (exothermic).
What can be concluded from this table?