Algorithm A1: length(s) 1. Initialize len to 0. 2. Set a variable to the beginning index of string s. 3. Repeat the following step till the string terminator is encountered. 4. len = len +1 5. Exit Implement the above algorithms using functions
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1. Initialize len to 0.
2. Set a variable to the beginning index of string s.
3. Repeat the following step till the string terminator is encountered.
4. len = len +1
5. Exit
Implement the above algorithms using functions.
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- Using binary search approach, write a python function named update_record, which takes the following inputs: 1: students_records – Nested List of Tuples. Each tuple of the list represents student's data. 2: ID – An ID of a student whose data has to be updated 3: record_title – type of data that has to be updated 4: data – A new data that should replace record_title data and update the record of students' data associated to specific ID. If ID is given as the data to be updated, then return a message that ID cannot be updated. If ID is not found in students_records, then return a message that Record not found. NOTE: The type of record_title input can be "ID", "Email", "Mid1" or "Mid2". Please use the same spelling for these types in your code, because the same have been used in test cases. Test cases are attached below: student_records = '[("aa02822", "ea02822", 80, 65),("ea02822", "ea02822@st.habib.edu.pk", 80, 65),("fa08877", "fa08877@st.habib.edu.pk", 66, 67),("gh04588",…python: answer in one line of code if possible, please def traditions_dict(adict): """ Question 6 Given a dictionary that maps a person to a list of their favorite GT traditions, return a dictionary with the value being the list sorted by the last letter of each tradition. If two traditions have the same last letter, sort by the first letter. HINT: This will require the use of lambda functions Args: adict (dict) Returns: dict >>> traditions_dict({"Jacob": ["The Horse", "Stealing the t", "Midnight Bud"], "Athena": ["Mini Five-Hundred", "Freshman Cake Race", "Buzzweiser Song"], "Liv": ["Freshman Cake Race", "George P. Burdell", "Buzzweiser Song"]}) {'Jacob': ['Midnight Bud', 'The Horse', 'Stealing the t'], 'Athena': ['Mini Five-Hundred', 'Freshman Cake Race', 'Buzzweiser Song'], 'Liv': ['Freshman Cake Race', 'Buzzweiser Song', 'George P. Burdell']} >>>…python code. instructions are given within the quotations for each function. 1) def invert_dict(d): """ Given a dictionary d, create the invert of the dictionary where the key is a value v in d, and v is mapped to a set of keys in original d whose values are equal to v. Return the inverted dictionary mapping value to set of keys """ return {1:1} 2) def histogram(words): """ Given a list of words, create a histogram dictionary where the key is the length of a word and the value is the count of how many words in the list are of that length. Return the histogram dictionary mapping length to word counts """ return {1:1} 3) def max_kv(d): """ Given a dictionary, return a tuple of key value pair where the key is the largest in d. """ return (1, {1}) 4) def run(): """ Get words list from the file listed in argv[1]; create histogram of count of each word length; create invert…
- def longest_unique_substring(s: str) -> str:"""Given a string <s>, return the longest unique substring that occurs within<s>.A unique substring is a substring within <s> which DOES NOT have anyrepeating characters. As an example, "xd" is unique but "xxd" is not.If there are two equal length unique substrings within <s>, return the onethat starts first (i.e., begins at a smaller index).tips:In order to get your function to run fast, consider using a dictionary tostore the indexes of previously seen characters, from there, you canfollow a set of rules based on each new character you see to determinethe length of the longest unique substring seen so far.>>> longest_unique_substring('aab')'ab' >>> longest_unique_substring('abcabcbb')'abc'"""def longest_unique_substring(s: str) -> str:"""Given a string <s>, return the longest unique substring that occurs within<s>.A unique substring is a substring within <s> which DOES NOT have anyrepeating characters. As an example, "xd" is unique but "xxd" is not.If there are two equal length unique substrings within <s>, return the onethat starts first (i.e., begins at a smaller index).tips:In order to get your function to run fast, consider using a dictionary tostore the indexes of previously seen characters, from there, you canfollow a set of rules based on each new character you see to determinethe length of the longest unique substring seen so far.>>> longest_unique_substring('aab')'ab' >>> longest_unique_substring('abcabcbb')'abc'""" RESTRICTIONS: - Do not add any imports and do it on python .Do not use recursion. Do not use break/continue.Do not use try-except statements.def longest_unique_substring(s: str) -> str:"""Given a string <s>, return the longest unique substring that occurs within<s>.A unique substring is a substring within <s> which DOES NOT have anyrepeating characters. As an example, "xd" is unique but "xxd" is not.If there are two equal length unique substrings within <s>, return the onethat starts first (i.e., begins at a smaller index).tips:In order to get your function to run fast, consider using a dictionary tostore the indexes of previously seen characters, from there, you canfollow a set of rules based on each new character you see to determinethe length of the longest unique substring seen so far.>>> longest_unique_substring('aab')'ab'""" RESTRICTIONS: - Do not add any imports and do it on python .Do not use recursion. Do not use break/continue.Do not use try-except statements.
- (C Language) The Fibonacci sequence begins with 0 and then 1 follows. All subsequent values are the sum of the previous two, for example: 0, 1, 1, 2, 3, 5, 8, 13. Complete the Fibonacci() function, which takes in an index, n, and returns the nth value in the sequence. Any negative index values should return -1.Task 2: Implement the function Searchingstrings that allow to search a sub-string in a given string and display the: First occurrence, Last occurrence, First occurrence from a given index and Last occurrence from a given index. You can use the following String methods: string. IndexOf(searchvalue, start) return the position of the first occurrence of specified character(s) in a string. string.lastIndexOf(searchvalue, start) return the position of the last occurrence of specified character(s) in a string. You can use the following string to test your solution: var letters = "abcdefghijklmnopqrstuvwxyzabcdefghijklm"; Write the code in a separate.js and separate.html file.g. Include a delete() function in LinearProbingHashST that deletes a key-value pair by changing the value to null (while leaving the key in place) and then deleting the pair from the table in resize(). The most difficult decision you must make is when to use resize(). Note: If a future put() action associates a new value with the key, you should replace the null value. Make sure that while deciding whether to enlarge or shrink the table, your programme takes into consideration both the number of such tombstone items and the number of vacant places.
- Implement the following function which compares two strings without using the library function. Prototype: int compare(char *str1, char *str2). The compare function returns 0 if str1 is equal to str2, returns 1 if str1 is greater than str2, and returns -1 if str2 is greater than str1. Then print the information in the main function.Use Python for this question: Write a function piggyBank that accepts a sequence of "coins" and returns counts of the coins and the total value of the bank. the coins will be given by a list of single characters, each one of 'Q','D','N',P' , representing quarter, dime, nickel, penny the function returns a tuple with two items: a dictionary with counts of each denomination. They should always be listed in the order 'Q','D','N',P' the total value in whole cents of the amount in the bank Output for this question is in the attached pictureIn kotlin, Write a recursive linear search function that takes a String and a Char and returns true if the String contains the Char. The base cases are that a) the length of the String is 0 or b) the first character in the String is the character we are searching for. then Modify the linear search function so that both the String and the Char are nullable. If either is null, return false.