Review Problem 6.073Ammonia reacts with oxygen as follows:4NH3(g) + 702(g)4NO2(g) + 6H20(g) AH° = -1132 kJCalculate the enthalpy change for the combustion of 7.76 mol of NH3.kJthe tolerance is +/-2%Select the thermochemical equation for the reaction in which one mole of H20 is formed.O 2/3NH3(g) + 7/602(g) → 2/3NO2(g) + H2O(g) AH° = -188.7 k)O 4NH3(g) + 702(g) -+ 4NO2(g) + H2O(g) AHº = -188.7 k)O 2/3NH3(g) + 7/602(g)→ 2/3NO2(g) + H20(g) AHO = -1132 kJO 2/3NH3(g) + 7/602(g) → 2/3NO2(g) + H20(g) AHº = -283.0 kJO NH3(g) + 7/402(g) → NO2(g) + 3/2H20(g) AHº= -283.0 kJ

Answered: Ammonia reacts with oxygen as follows:…

Ammonia reacts with oxygen as follows: 4NH3(g) + 702(g) → 4NO2(g) + 6H20(g) AH° = -1132 kJ Calculate the enthalpy change for the combustion of 7.76 mol of NH3. kJ

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter4: Energy And Chemical Reactions

Section4.8: Measuring Reaction Enthalpies: Calorimetry

Problem 4.9PSP

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Question

Review Problem 6.073
Ammonia reacts with oxygen as follows:
4NH3(g) + 702(g)
4NO2(g) + 6H20(g) AH° = -1132 kJ
Calculate the enthalpy change for the combustion of 7.76 mol of NH3.
kJ
the tolerance is +/-2%
Select the thermochemical equation for the reaction in which one mole of H20 is formed.
O 2/3NH3(g) + 7/602(g) → 2/3NO2(g) + H2O(g) AH° = -188.7 k)
O 4NH3(g) + 702(g) -
+ 4NO2(g) + H2O(g) AHº = -188.7 k)
O 2/3NH3(g) + 7/602(g)
→ 2/3NO2(g) + H20(g) AHO = -1132 kJ
O 2/3NH3(g) + 7/602(g) → 2/3NO2(g) + H20(g) AHº = -283.0 kJ
O NH3(g) + 7/402(g) → NO2(g) + 3/2H20(g) AHº
= -283.0 kJ

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