Analysis of a blood sample for inorganic phosphate gives (4.5, 4.20, 3.6, 4.17, 3.88) mg% phosphate. The value of Standard deviation = +- 0.573 a) True O b) False
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- Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln Tunnel connecting New York and New Jersey. The total concentrations ( ± standard deviation) of m- and p-xylene wereTurnpike: 31.4 ± 27.0 μg/m3 (32 measurements)Tunnel: 54.9 ± 29.8 μg/m3 (32 measurements)Do these results different at the 95% confidence level?In a gravimetric chloride analysis, it was found that 0.82g AgCl was obtained from an unknown that had a mass of 0.3g a. What is the mass of CL in the original sample b. Percentage chloride in original sample c. Average percent chloride d. Standard deviation e. Relative standard deviation expressed as a percentAnalysis of several plant-food preparations for potassium ion yielded the following data: Sample Percent K+1 6.02, 6.04, 5.88, 6.06, 5.822 5.29, 5.13, 5.14, 5.28, 5.20 The preparations were randomly drawn from the same population.(a) Find the mean and standard deviation s , variance , andCV for each sample.
- Analysis of several plant-food preparations for potassium ion yielded the following data: Sample Percent K+ 1 3.90, 3.96, 4.16, 3.96 2 4.48, 4.65, 4.68, 4.42 Find the mean ; standard deviation variance and RSD for each sample.In a gravimetric chloride analysis, it was found that 0.82g AgCl and 0.80g AgCl was obtained from an unknown that had a mass of 0.3g a. What is the mass of CL in the original sample for each b. Percentage chloride in original sample for each c. Average percent chloride d. Standard deviation e. Relative standard deviation expressed as a percent1. Replicate analyses of the lead content in a blood sample gave the following results: 0.789, 0.781, 0.795, 0.792, and 0.784 ppm Pb. Calculate the mean, standard deviation, variance, relative standard deviation, and standard deviation of the mean of the data.
- 2. A study of body mass index (BMI) in adults showed that for men aged 40–44, the mean BMI level is 26.7 with a standard deviation of 3.7. Assuming a normal distribution, what percentage of men in this age group have a BMI between 30.0 and 35.0?The following results were obtained in the replicate determination of the lead content of a blood sample: 0.752, 0.756, 0.752, 0.751, and 0.760 ppm Pb. Calculate the ff: (a) mean (b) standard deviation (c) variance (d) RSD (e) CV (f) RangeThe following data represented the concentration of ofloxacin present in chicken meat samples: 4.17, 4.40, 4.35, 4.35, 4.20, 4.16,4.20 and 4.17. Estimated the % relative standard deviation.
- Replicate water samples are analyzed for water hardness with the following results: 102.2, 102.8, 103.1, and 102.3 ppm CaCO3. What is the (a) the standard deviation, (b) the relative standard deviation, (c) variance.Calculate the mean and sample standard deviation for the following data: 90.0, 90.0, 85.0, 83.0, 80.0, 78.0, 77.0, 75.0, 70.0. Group of answer choices 79.8 ±± 5.83 79.8 ±± 6.23 80.9 ±± 6.75 80.9 ±± 6.37According to the information given below, compute the correlation coefficient and the covariance coefficient between stock A and stock B. Standard deviation of the portfolio (stock A and stock B) : 0.37Standard deviation of the stock A : 0.38Standard deviation of the stock B : 0.43Weight for stock A : 0.60Weight for stock B : 0.40NOTE: PLEASE SHOW HOW YOU COMPUTE EACH OF THE ITEMS.