A sample containing an unknown quantity of cadmium in a water sample gave a reading of 1.4 in an atomic spectrometer. The sample was spiked with a 2 ppm mercury standard and gave a reading of 2.5. The instrument give a reading of zero with no sample. What is the concentration of cadmium in the unknown sample?
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A sample containing an unknown quantity of cadmium in a water sample gave a reading of 1.4 in an atomic spectrometer. The sample was spiked with a 2 ppm mercury standard and gave a reading of 2.5. The instrument give a reading of zero with no sample. What is the concentration of cadmium in the unknown sample?
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- For EACH type of gravimetric analysis:Give actual applications of each analysis. Include the SPECIFIC methodology for each sample chosen.1. A student performed this experiment and obtained the following concentration values: 0.02813 M, 0.02802, and 0.02788 M a. what is the mean concentration? b. what is the standard deviation of these results? 3. how would the following errors affect the concentration of Cl- obtained in question 2b? give your reasoning in each case. a. the student read the molarity of AgNo3 as 0.02104M instead of 0.02014M b. the student was past the endpoint of titration when he took the final buret reading.What are the differences between systematic and random errors and how do they effect accuracy and precision? In what circumstances would you use standard addition (versus a normal calibration curve) to determine the amount of an analyte in a sample? A urine sample, containing analyte Z is analysed by the standard addition method where 5 mL of the original sample was mixed with increasing amounts of a Z standard and each solution diluted to a volume of 50 mL prior to analysis. A plot of the final concentration of the standard in each of the 50 mL samples (x axis) versus The measured signal from the analysis of each 50 mL sample (on y axis) produced a straight line with the general equation: y = 44.72x + 4.06 what was the final concentration of Z in the 50 mL standard addition sample? what was the initial concentration of Z in the original urine sample?
- A stock solution of 0.225 +/- 0.003 M NaNO2 was transferred to a 100 mL volumetric flask (class A) and diluted to the mark. If 7 mL of the stock solution was transferred using one 5-mL and two 1-mL volumetric pipettes, what is the new concentration of the solution and the uncertainty?A method for the detection of morphine is used to generate a calibration curve in which the assay response (y) is plotted versus morphine concentration (x, in mg/L). This gives a straight line with a slope (m) of 0.241 and a y-intercept (b) of 0.011, where y = mx + b. The slope of this line has a standard deviation of ±0.007, and the standard deviation of the intercept is ±0.006. If the sample from an athlete gives a response of 0.506 ± 0.013 in this method, what is the concentration of morphine in the sample and estimated precision of this concentration?An excess of 0.34 mg Pb is obtained from an assay test determined in an analysis. What is the percent relative error in ppt if the mass of the sample is 550 g?
- Give the standard deviation of these three molaritys. 0.0366 0.0373 0.0370Molarity trail 1 0.0366 trail 2 0.0373 trail 3 0.0370 Calculate the standard deviation. Calculate the Relative Standard deviation of molarity to 3 sig figs.The method of standard additions was used to determine nitrite in a soil sample. A 1.00-mL portions of the soil extract sample was transferred to four 25-mL volumetric flasks. To each flask, increment volumes of a 1.00 x10-3M nitrite was added according to the table below. A colorimetric reagent was added to each flask to convert the nitrite into a colored product, and finally diluted to volume. What is the concentration of the nitrite in the soil extract based on the absorbance data below (with blank correction included)? Vol. of standard nitrite added, ml Absorbance 5.00 0.079 10.00 0.161 15.00 0.236 20.00 0.318 25.00 0.403
- In a chromatography experiment, a solution containing 0.083 7 M X and 0.066 6 M S gave peak areas of AX = 423 and AS 5 347. (Areas are measured in arbitrary units by the instrument.) To analyze the unknown, 10.0 mL of 0.146 M S were added to 10.0 mL of unknown, and the mixture was diluted to 25.0 mL in a volumetric flask. This mixture gave the chromatogram in Figure 5-8, with peak areas AX = 553 and AS = 582. Find the concentration of X in the unknown.Identify and explain the mistakes made in the following laboratory protocols: A 1250 mg sample of NaOH was weighed using an analytical balance. The pellets were directly transferred in the balance pans, pellets were gradually added until the reading of the balance was near to 0.2000 mg.A volume of 250 ml of a 0.05 M solution of a reagent of formula weight (relative molecular mass) 40 was made up, the weighing being done by difference. The standard deviation of each weighing was 0.0001 g. The standard deviation of the volume of solvent used was 0.05 ml. Express this as a relative standard deviation. Hence calculate the relative standard deviation of the molarity of the solution.