Answer the question please? What is the return value of the following recursive algorithm when the input arguments are A=[0,0,1,0,0,1,0,1] and pos=7? function F(A,pos) if(pos<0) return 0 if(pos==length(A)-1 or pos==0 or A[pos-1]==1 or A[pos+1]==1) return 0 + F(A,pos-1) if(A[pos-1]==0 and A[pos+1]==0) return 1+ F(A,pos-1) One of these options below are correct, which one? 7 2 8 5 none of the others

Given the recursive function definition:s(n) = 5 + n * s(n-1) + s(n-2) s(0) = 1 s(1) = 3Question:  Evaluate: s(3)

Midterm Practice Problems 1. Use recursion to write a function count_ones that returns how many Is there are in a number n when represented in decimal (base 10). For example, 1231 has two 1s. You can assume that n is nonnegative and at most 9 digits long. Do not use global (or static) variables. In main perform at least three tests of count_ones and use assert to check that the returned value is correct. Your function should have the following prototype: // count_ones (n) returns the number of is in the decimal representation of n // requires: 0 <= n < 10^9 int count_ones (int n);

Write a recursive Racket function "update-if" that takes two functions, f and g, and a list xs as parameters and evaluates to a list. f will be a function that takes one parameter and evaluates true or false. g will be a function that takes one parameter and evaluates to some output. The result of update-if should be a list of items such that if x is in xs and (f x) is true, then (g x) is in the list. The output list's elements should keep the input list's items in the same relative order. For example (update-if even? add1 '(1 2 3 4)) should evaluate to '(3 5) because 2 and 4 make even? true and add1 turns 2 and 4 into 3 and 5.