True or false the number of atomic orbitals usedbased on molecular Orbital theory,the number of atomic prbitals usedwill equal to the num ber ofmole calar orlbitals formed1 Electrocyclic reaction will occur whenlobes Of opposite phases of theorbltals overlap to formed a bondresulting in a symmetry allowe dprocessThe reaction below will form 3bromindted productsBrcencozlz.o

MOT is a method for describing the electronic structure of molecules using quantum mechanics.

based on molecular Orbital theory, the number of atomic orbitals used will equal to the number of mole cular orbitals formed. • tlectrocyclic reaction will occur when lobes of opposite phases of the orbitals overlap to formed a bond resulting in a symmetry aowed process The reaction below will form 3 brominated pro ducts chs -Br

based on molecular Orbital theory, the number of atomic orbitals used will equal to the number of mole cular orbitals formed. • tlectrocyclic reaction will occur when lobes of opposite phases of the orbitals overlap to formed a bond resulting in a symmetry aowed process The reaction below will form 3 brominated pro ducts chs -Br

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter17: Conjugation And Molecular Orbital (mo) Theory

Section: Chapter Questions

Problem 8CTQ

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Similar questions

The molecular ion HeH+ has an equilibrium bond length of 0.774 Å. Draw an electron correlation diagram for this ion, indicating the occupied MOs. Is HeH+ paramagnetic? When HeH+ dissociates, is a lower energy state reached by forming He+H+ or He++H ?
The Be2 molecule has been detected experimentally. It has a bond length of 2.45 Å and a bond dissociation energy of 9.46kJmol1 . Write the ground-state electron configuration of Be2 and predict its bond order using the theory developed in the text. Compare the experimental bonding data on Be2 with those recorded for B2,C2,N2, and O2 in Table 6.3. Is the prediction that stems from the simple theory significantly incorrect?
Discuss the nature of the bonding in the nitrite ion (NO2) . Draw the possible Lewis resonance diagrams for this ion. Use the VSEPR theory to determine the steric number, the hybridization of the central nitrogen atom, and the geometry of the ion. Show how the use of resonance structures can be avoided by introducing a de-localized MO. What bond order does the MO model predict for the NO bonds in the nitrite ion?
(a) Using only the valence atomic orbitals of a hydrogenatom and a fluorine atom, and following the model ofFigure 9.46, how many MOs would you expect for the HFmolecule? (b) How many of the MOs from part (a) would beoccupied by electrons? (c) It turns out that the difference inenergies between the valence atomic orbitals of H and F aresufficiently different that we can neglect the interaction ofthe 1s orbital of hydrogen with the 2s orbital of fluorine.The 1s orbital of hydrogen will mix only with one 2p orbitalof fluorine. Draw pictures showing the proper orientationof all three 2p orbitals on F interacting with a 1s orbitalon H. Which of the 2p orbitals can actually make a bondwith a 1s orbital, assuming that the atoms lie on the z-axis?(d) In the most accepted picture of HF, all the other atomicorbitals on fluorine move over at the same energy into themolecular orbital energy-level diagram for HF. These arecalled “nonbonding orbitals.” Sketch the energy-level diagramfor HF using…
The following is part of a molecular orbital energy-level diagramfor MOs constructed from 1s atomic orbitals. (a) What labels do we use for the two MOs shown? (b) Forwhich of the following molecules or ions could this be theenergy-level diagram:H2, He2, H2+, He2+, or H2-?(c) What is the bond order of the molecule or ion? (d) If anelectron is added to the system, into which of the MOs will itbe added? [
What is the orientation of the two unhybridized p orbitals on Be with respect to thetwo Be¬F bonds?
How many π molecular orbitals (π-MOs) are formed from the linear combination of atomicorbitals (AOs) contributing to the π-bonding in pentene?
a-Draw a molecular orbital (MO) energy level diagram for NO. Label the atomic orbitals, MOs and identify the frontier orbitals. b-Explain the differences in bond dissociation energies and bond lengths on addition and removalof an electron from NO.
The sulfate ion can be represented with four S—O bonds orwith two S—O and two S=O bonds. (a) Which representation is better from the stand point of formal charges? (b) What is theshape of the sulfate ion, and what hybrid orbitals of S are postu-lated for the σ bonding? (c) In view of the answer to part (b),what orbitals of S must be used for the π bonds? What orbitalsof O? (d) Draw a diagram to show how one atomic orbital fromS and one from O overlap to form a π bond.
Antibonding molecular orbitals can be used to make bondsto other atoms in a molecule. For example, metal atomscan use appropriate d orbitals to overlap with the π*2p orbitalsof the carbon monoxide molecule. This is calledd-π backbonding. (a) Draw a coordinate axis system inwhich the y-axis is vertical in the plane of the paper andthe x-axis horizontal. Write “M” at the origin to denote ametal atom. (b) Now, on the x-axis to the right of M, drawthe Lewis structure of a CO molecule, with the carbon nearest the M. The CO bond axis should be on the x-axis.(c) Draw the CO π*2p orbital, with phases (see the “CloserLook” box on phases) in the plane of the paper. Two lobesshould be pointing toward M. (d) Now draw the dxy orbitalof M, with phases. Can you see how they will overlap withthe π*2p orbital of CO? (e) What kind of bond is being madewith the orbitals between M and C, σ or π ? (f) Predict whatwill happen to the strength of the CO bond in a metal–COcomplex compared to CO alone.
β-Carotene is the compound responsiblefor the orange color of carrots and is theprecursor to vitamin A. Judging from theLewis structure shown here, how many πbonds does β-carotene have?
Select one: True or False 1- Besides providing the largest suitable number of valance orbitals for covalent bond formation it can determine the final shape of the molecule for example Sp hybridization leads to a diagonal planner molecule, SP2 hybridization while Sp3 hybridization leads a pyramidal (tetrahydral shape) 2- About the underlying compound ( in the images ) , it it’s a calcium complex of EDTA used to treat metal toxicities like pulmbism in order to avoid hypocalcaemia.