Butane, CHo, is an easily liquefied gaseous fuel. Calculate the density of butane gas at 0.557 atm and 22 "C. Give the answer in grams per liter. Given that R 0.0821 L-atm/(mol-K), AW of C = 12.01 amu, and AW of H = 1.01 amu g/l 1.35 a O g/l 2.32.b O g/l 1.56.c O g/L 2.08 d O g/L 1.83.e O

Butane, CHo, is an easily liquefied gaseous fuel. Calculate the density of butane gas at 0.557 atm and 22 "C. Give the answer in grams per liter. Given that R 0.0821 L-atm/(mol-K), AW of C = 12.01 amu, and AW of H = 1.01 amu g/l 1.35 a O g/l 2.32.b O g/l 1.56.c O g/L 2.08 d O g/L 1.83.e O

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter13: Gases

Section: Chapter Questions

Problem 18QAP

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

Butane, CH10, is an easily liquefied gaseous fuel. Calculate the density of butane gas at 0.557 atm and 22 °C. Give the
answer in grams per liter. Given that R 0.0821 L-atm/(mol-K), AW of C = 12.01 amu, and AW of H = 1.01 amu
g/L 1.35 a O
g/l 2.32.b O
g/L 1.56.c O
g/L 2.08 d O
g/l 1.83.e O

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