C programming I'm trying to fix memory leak but it kept giving that one error. Where did I go wrong? #include #include void printArray(int *arr, int size){    int i;    if (arr != NULL)    {    for( i = 0; i < size; i++) {        // Print each element out        printf("%d", *(arr+i));                  //Print addresses of each element        printf("%p", (arr+i));              //Printing a new line        printf("\n");    } }   } int main() {    // Allows user to specify the original array size, stored in variable n1.    printf("Enter original array size: ");    int n1 = 0;    scanf("%d", &n1);    //a- Create a new array *a1 of n1 ints using malloc    int *a1 = malloc(n1 * sizeof(int));    //b- Remove comments for if statment below    //b- Set each element in a1 to 100 + indexValue ??    if(a1 == NULL) { printf("Error! memory not allocated.");    exit(0); }    int i;    for (i = 0; i < n1; i++)    {        a1[i] = 100 + i;    }    printf("Printing the first array allocated using malloc\n");    //c- Print each element and addresses out (to make sure things look right)    printArray(a1, n1);    // User specifies the new array size, stored in variable n2.    printf("\nEnter new array size: ");    int n2 = 0;    scanf("%d", &n2);    //d- Dynamically change the array a1 to size n2    a1 = malloc (n2 * sizeof(int));    //e- Remove comments for if statment below    if(a1 == NULL)    {    printf("Error! memory not allocated.");    exit(0);    }               //e- If the new array is a larger size, set all new members to 200 + indexValue.    if (n2 > n1)    {        int i;        for (i = 0; i < n2; i++)        {            a1[i] = 100 + i;        }    }    printf("Printing the reallocated array: \n");    //f- Print each element and addresses out (to make sure things look right)    printArray(a1, n2);    //g-Free the allocated memory for a1    free(a1);    a1 = NULL;    printf("\nEnter new array size to be initialized with 0: ");    int n3 = 0;    scanf("%d", &n3);    //h- Remove comments for if statement    //h- Using calloc create a new array and assign it to a2    //with new array size, stored in variable n3.    int *a2 =calloc(n3, sizeof(int)); if(a2 == NULL) {    printf("Error! memory not allocated.");    exit(0);    }    printf("Printing the array created using calloc: \n");    //i- Print array a2 with size n3    printArray(a2, n3);       //j- Print array a1 again, How you can fix this problem    printf("Printing deallocated array a1: \n");    printArray(a1, n2);    // Done with arrays now, free the and assign NULL    free(a2);    a1 = NULL;    a2 = NULL;      printf("Program Successfully Completed!");    return 0; }

C programming I'm trying to fix memory leak but it kept giving that one error. Where did I go wrong?

#include <stdlib.h>
#include <stdio.h>

void printArray(int *arr, int size){
   int i;
   if (arr != NULL)
   {
   for( i = 0; i < size; i++) {
       // Print each element out
       printf("%d", *(arr+i));          
       //Print addresses of each element
       printf("%p", (arr+i));      
       //Printing a new line
       printf("\n");
   }
}  
}

int main() {

   // Allows user to specify the original array size, stored in variable n1.
   printf("Enter original array size: ");
   int n1 = 0;
   scanf("%d", &n1);
   //a- Create a new array *a1 of n1 ints using malloc
   int *a1 = malloc(n1 * sizeof(int));
   //b- Remove comments for if statment below
   //b- Set each element in a1 to 100 + indexValue ??
   if(a1 == NULL)
{
printf("Error! memory not allocated.");
   exit(0);
}
   int i;
   for (i = 0; i < n1; i++)
   {
       a1[i] = 100 + i;
   }

   printf("Printing the first array allocated using malloc\n");
   //c- Print each element and addresses out (to make sure things look right)
   printArray(a1, n1);

   // User specifies the new array size, stored in variable n2.
   printf("\nEnter new array size: ");
   int n2 = 0;
   scanf("%d", &n2);
   //d- Dynamically change the array a1 to size n2
   a1 = malloc (n2 * sizeof(int));

   //e- Remove comments for if statment below
   if(a1 == NULL)
   {
   printf("Error! memory not allocated.");
   exit(0);
   }
  
       
   //e- If the new array is a larger size, set all new members to 200 + indexValue.
   if (n2 > n1)
   {
       int i;
       for (i = 0; i < n2; i++)
       {
           a1[i] = 100 + i;
       }
   }

   printf("Printing the reallocated array: \n");
   //f- Print each element and addresses out (to make sure things look right)
   printArray(a1, n2);

   //g-Free the allocated memory for a1
   free(a1);
   a1 = NULL;

   printf("\nEnter new array size to be initialized with 0: ");
   int n3 = 0;
   scanf("%d", &n3);
   //h- Remove comments for if statement
   //h- Using calloc create a new array and assign it to a2
   //with new array size, stored in variable n3.
   int *a2 =calloc(n3, sizeof(int));

if(a2 == NULL)
{
   printf("Error! memory not allocated.");
   exit(0);
   }

   printf("Printing the array created using calloc: \n");
   //i- Print array a2 with size n3
   printArray(a2, n3);
  
   //j- Print array a1 again, How you can fix this problem
   printf("Printing deallocated array a1: \n");
   printArray(a1, n2);

   // Done with arrays now, free the and assign NULL

   free(a2);
   a1 = NULL;
   a2 = NULL;  

   printf("Program Successfully Completed!");
   return 0;
}