C16H34 + 16.28 O2 +1.42 NH3 → 1.65 C4.4H7.301.2No.86 + 8.74 CO2 + 13.11 H2O For a particular bacterial strain, the molecular formula was determined to be C4.4H7.301.2No.86. These bacterial cells are grown under aerobic conditions with hexadecane (C16H34) as substrate. Assume that 60% of the hexadecane is used for producing cells (also called biomass) and the remaining 40% of the hexadecane is used for other cell functions. You have been put in charge of a small batch fermenter for growing the bacteria and aim to produce 10 kg of cells for inoculation of a pilot-scale reactor. a) Assuming this 60% conversion, what is the yield of cells from hexadecane in kg/kg?

Curren'S Math For Meds: Dosages & Sol
11th Edition
ISBN:9781305143531
Author:CURREN
Publisher:CURREN
Chapter10: Reconstitution Of Powdered Drugs
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C16H34 + 16.28 O2 +1.42 NH3 → 1.65 C4.4H7.301.2No.86 + 8.74 CO2 + 13.11 H20
For a particular bacterial strain, the molecular formula was determined to be C4.4H7.301.2No.86. These
bacterial cells are grown under aerobic conditions with hexadecane (C16H34) as substrate.
Assume that 60% of the hexadecane is used for producing cells (also called biomass) and the remaining
40% of the hexadecane is used for other cell functions. You have been put in charge of a small batch
fermenter for growing the bacteria and aim to produce 10 kg of cells for inoculation of a pilot-scale
reactor.
a) Assuming this 60% conversion, what is the yield of cells from hexadecane in kg/kg?
Answer: 0.401
Transcribed Image Text:C16H34 + 16.28 O2 +1.42 NH3 → 1.65 C4.4H7.301.2No.86 + 8.74 CO2 + 13.11 H20 For a particular bacterial strain, the molecular formula was determined to be C4.4H7.301.2No.86. These bacterial cells are grown under aerobic conditions with hexadecane (C16H34) as substrate. Assume that 60% of the hexadecane is used for producing cells (also called biomass) and the remaining 40% of the hexadecane is used for other cell functions. You have been put in charge of a small batch fermenter for growing the bacteria and aim to produce 10 kg of cells for inoculation of a pilot-scale reactor. a) Assuming this 60% conversion, what is the yield of cells from hexadecane in kg/kg? Answer: 0.401
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