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Calcium Bromide, CaBr2, reacts with oxygen gas, O2.

Calcium Bromide, CaBr2, reacts with oxygen gas, O2.

Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter9: Chemical Quantities
Section: Chapter Questions
Problem 12CR: What is meant by a limiting reactant in a particular reaction? In what way is the reaction...
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15.Calcium Bromide, CaBr2, reacts with oxygen gas, 02. a. What are the products in the reaction? b. Balance the reaction. c. What is the molar mass of Calcium Bromide? d. How many moles of oxygen will it take to create 6 moles of the compound made in the product? e. What would be the limiting reactant if there were 4 moles of CaBr2 and 4 moles of O2 to make moles of CaO? D.Focus ELT
Transcribed Image Text:15.Calcium Bromide, CaBr2, reacts with oxygen gas, 02. a. What are the products in the reaction? b. Balance the reaction. c. What is the molar mass of Calcium Bromide? d. How many moles of oxygen will it take to create 6 moles of the compound made in the product? e. What would be the limiting reactant if there were 4 moles of CaBr2 and 4 moles of O2 to make moles of CaO? D.Focus ELT
Expert Solution
Step 1

Solution:- Reaction takes place between CaBr2 & O2 :-

CaBr2 + O2(g) → CaO + Br2 

Calcium bromide would react with oxygen to give calcium oxide and broime.

(a) The products would form are Calcium oxide (CaO) & Bromine (Br).

(b) Balancing of chemical reaction.

Reaction :- CaBr2 + O2 →CaO + Br2 

(1) Multiply CaO by 2 to get 2 oxygen on both side, It would become:- CaBr2 + O2 →2CaO + Br2

Now, we get 2 Ca on product side.

(2) Multiply CaBr by 2 to get 2 'Ca' on both sides, we would get:- 

2CaBr2 + O2 →2CaO + Br2

(3) Now we have to multiply Br2 on product side to get 4 Br on both sides.

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