Calculate the pH at the halfway point and at the equivalence point for each of the following titrations. a. 100.0 mL of 0.10 M HC-H5O2 (K₂ = 6.4 × 10−5) titrated by 0.10 M NaOH pH at the halfway point pH at the equivalence point = b. 100.0 mL of 0.30 M C₂H5NH₂ (K₁ = 5.6 × 10-4) pH at the halfway point pH at the equivalence point = c. 100.0 mL of 0.70 M HCl titrated by 0.25 M NaOH pH at the halfway point = pH at the equivalence point = titrated by 0.10 M HNO3

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Chapter14: Acid- Base Equilibria
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Calculate the pH at the halfway point and at the equivalence point for each of the following titrations.
a. 100.0 mL of 0.10 M HC7H5O₂ (K₂ = 6.4 × 10-5) titrated by 0.10 M NaOH
pH at the halfway point =
pH at the equivalence point =
b. 100.0 mL of 0.30 M C₂H5NH₂ (K₁ = 5.6 × 10-4) titrated by 0.10 M HNO3
pH at the halfway point
pH at the equivalence point =
c. 100.0 mL of 0.70 M HCl titrated by 0.25 M NaOH
pH at the halfway point =
pH at the equivalence point =
Transcribed Image Text:Calculate the pH at the halfway point and at the equivalence point for each of the following titrations. a. 100.0 mL of 0.10 M HC7H5O₂ (K₂ = 6.4 × 10-5) titrated by 0.10 M NaOH pH at the halfway point = pH at the equivalence point = b. 100.0 mL of 0.30 M C₂H5NH₂ (K₁ = 5.6 × 10-4) titrated by 0.10 M HNO3 pH at the halfway point pH at the equivalence point = c. 100.0 mL of 0.70 M HCl titrated by 0.25 M NaOH pH at the halfway point = pH at the equivalence point =
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