can someine show me how to do this using:  48.5 g of cold water starting at 14 C and 48.1g of hot water starting at 38 C SAMPLE CALCULATION: Let’s say you had 20 g of cold water starting at 25 C and 30 g of hot water starting at 70 C, you would set it up like this [NOTE: I am using c in J/gC]: (20)(4.18)(x-25) = - (30)(4.18)(x -70) Now use algebra… (83.6)(x-25) = - (125.4)(x-70) [distribute through the parenthesis] 83.6x-2090 = -125.4x + 8778 [add 125.4x to both sides] 209x-2090 = 8778  [add 2090 to both sides] 209x = 10868 [divide both sides by 209] X=52 C instead using 48.5 g of cold water starting at 14 C and 48.1g of hot water starting at 38 C

Chemistry for Engineering Students
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ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter9: Energy And Chemistry
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can someine show me how to do this using:  48.5 g of cold water starting at 14 C and 48.1g of hot water starting at 38 C

SAMPLE CALCULATION: Let’s say you had 20 g of cold water starting at 25 C and 30 g of hot water starting at 70 C, you would set it up like this [NOTE: I am using c in J/gC]:

(20)(4.18)(x-25) = - (30)(4.18)(x -70) Now use algebra…

(83.6)(x-25) = - (125.4)(x-70) [distribute through the parenthesis]

83.6x-2090 = -125.4x + 8778 [add 125.4x to both sides]

209x-2090 = 8778  [add 2090 to both sides]

209x = 10868 [divide both sides by 209]

X=52 C

instead using 48.5 g of cold water starting at 14 C and 48.1g of hot water starting at 38 C

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