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can someone explain these calculations to me?
At first, a standard curve is made using the OD of protein of known concentrations, i.e., ODs mentioned for blank to 20ug/ml protein concentration and a linear trend line is obtained with the equation mentioned in step 2. This equation is compared with the straight line equation "Y=mX+c" where Y is the OD, X is protein concentration, m is the tangent/slope of the line and c is the intercept. We can calculate unknown X (concentration) using this equation if we have the Y(OD) value by modifying the formula to X="(Y-c)/m".
Now we have a protein solution of unknown concentration that has been diluted 50 times and 10ul of the diluted sample has been used to obtain OD. Using the trendline equation mentioned earlier, the protein content of the 10ul diluted sample is calculated to be 16.57.
Further, the protein content for 1 ml solution is calculated by multiplying with 100 and the concentration of diluted sample expressed in ug/ml.
Since the original sample was diluted 50 times in the first place, the concentration is multiplied again by 50 and the original concentration of the protein sample is obtained.
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- Table 2. Volume of BSA, protein content, and absorbance readings of reference solutions Solution Volume of BSA standard solution (μL) Protein content(μg/mL) Absorbance value At 595 nm 1 0 0 0 2 10 1 0.022 3 30 3 0.065 4 50 5 0.106 5 70 7 0.178 6 100 10 0.299 7 120 12 0.380 Make a graph by plotting the absorbance values versus the BSA protein content (in μg) for theseven reference solutions. When constructing the graph, be…Calculate protein concentration in unknown samples 1, 2, 3: Absorbance of Unknown 1 = 0.541 Absorbance of Unknown 2 = 0.85 Absorbance of Unknown 3 = 1.02 Standard Curve: Y = 0.0073x1.0 ml of serum albumin (BSA) solution was precisely diluted to 100 ml with a buffer solution, and the absorbance at 280 nm was measured from this buffer solution at a distance of 1 cm from the light. The result was A=1.0. BSA is 0.1%(=0.1g/l). The absorptivity is e(0.1%)=0.667, so 1g/l solution gives an absorbance of 0.667. What was the original protein content? Report in the result unit mg/ml with an accuracy of 0.1 mg.
- Solution Absorbance mg/ml aspirin Standard solution - 1.6 mg/mL A 0.638 0.08 mg/mL B 0.504 0.064 mg/mL C 0.376 0.048 mg/mL D 0.259 0.032 mg/mL E 0.126 0.016 mg/mL A = -log T where T = %T ÷ 100 Construct a callibration curve using the above data. Absorbance should be on the vertical axis and "mg/mL of acetylsalicylic acid" on the horizontal axis. The line should go through the origin. Using the data provided, the graph you have generated, and the procedure that was used to generate the solutions which were examined by spectroscopy, calculate the amount of acetylsalicylic acid per tablet. Commercial tablet 1 labelled as 100 mg enteric coated Absorbance = 0.16 Commercial tablet 2 labelled as 300 mg Absorbance = 0.45 Student prepared tablet from practical 5 Absorbance = 0.19 Using the data provided, the graph you have generated, and the procedure that was used…pH 3.5 4.5 5.5 6.5 7.5 8.5 Absorbance 0.098 0.027 0.068 0.028 0.032 0.054 Concentration in diluted supernatant (mg/ml) 0.196 0.054 0.136 0.0056 0.0064 0.0108 Concentration in undiluted supernatant (mg/ml) 0.98 0.27 0.68 0.28 0.32 0.54 Formula for the amount (g) of soluble proteins in the soy flour extract: In 15 ml of soy flour extract (with 1/50 dilution), Soluble protein (g) = (C x V x F) / 1000 C = concentration (mg/ml); F = dilution factor; V = volume of solution (ml) Calculate the % solubility of protein in the soy flour (Assume the soy flour contains 35% protein (w/w))pH 3.5 4.5 5.5 6.5 7.5 8.5 Absorbance 0.098 0.027 0.068 0.028 0.032 0.054 Concentration in diluted supernatant (mg/ml) 0.196 0.054 0.136 0.0056 0.0064 0.0108 Concentration in undiluted supernatant (mg/ml) 0.98 0.27 0.68 0.28 0.32 0.54 Formula for the amount (g) of soluble proteins in the soy flour extract: In 15 ml of soy flour extract (with 1/50 dilution), Soluble protein (g) = (C x V x F) / 1000 C = concentration (mg/ml); F = dilution factor; V = volume of solution (ml) Calculate the amount of soluble protein (in grams) in the soy flour extract
- Guanosine (C10H13N5O5) in solution has a maximum absorbance at a wavelength of 275 nm. The molar extinction co-efficient at this wavelength is 84M−1cm−1and the path length is 24.7 cm. Through the use of a spectrophotometer, it is found that the that A275= 1.48. What is the concentration of the guanosine solution in grams/litre? Molecular weights (g/mol): C-12, H-1, N-14, O-16 Select one: A. 0.201869 g/L B. 0.435188 g/L C. 0.059919 g/L D. 0.294046 g/L E. 0.000713 g/LUsing the equation for the best-fit straight line through your data, the average absorbance of your unknown samples U1 and U2, and any dilution factors (DON’T LEAVE OUT THE DILUTION FACTOR), calculate the concentration of protein in the original unknown protein sample. y = 1.6849x + 0.0414R² = 0.9904Rx Of oxacinophtalmic solution 3% Disp. 10 mL How many milligrams of axacin contained in each milliter of the dispensed prescription?
- You obtained the following raw data when setting up a Biuret standard curve: BSA (mg/ml) Absorbancy 540nm 0 0.158 1 0.210 2 0.260 3 0.305 4 0.360 5 0.410 6 0.455 7 0.510 8 0.530 9 0.550 10 0.554 After blanking against a biuret-dH2O sample, the protein concentration of an unknown sample was determined using the same method and an absorbancy of 0.262 was obtained. Set up a standard curve, excluding outliers (experimental and statistical) and determine the protein concentration in the unknown sample in mg / ml (up to 3 significant figures).The protein concentration of a known standard is 100mg/mL If you prepared a serial dilution, mixing 10μL of protein with 40μL of water what would be concentrations of the first 3 dilutions?A 2.5mg/ml solution of ampicillin is available for use, what volume would youadd to 200ml of LB medium to obtain a final concentration of 50µg/ml ofampicillin?