Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S, (g) + C(s) = CS,(g) Ke = 9.40 at 900 K How many grams of CS, (g) can be prepared by heating 16.6 mol S, (g) with excess carbon in a 6.90 L reaction vessel held at 900 K until equilibrium is attained? g mass of CS, (g):

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Chapter5: Gases
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General Chemistry 4th Edition
McQuarrie Rock Gallogly
University Science Books
presented by Macmillan Learning
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is
S,(g) + C(s) = CS, (g)
= 9.40 at 900K
Ko
How many grams of CS, (g) can be prepared by heating 16.6 mol S,(g) with excess carbon in a 6.90 L reaction vessel held
2,
at 900 K until equilibrium is attained?
mass of CS,(g):
Question Source: MRG - General Chemistry Publis
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Transcribed Image Text:General Chemistry 4th Edition McQuarrie Rock Gallogly University Science Books presented by Macmillan Learning Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S,(g) + C(s) = CS, (g) = 9.40 at 900K Ko How many grams of CS, (g) can be prepared by heating 16.6 mol S,(g) with excess carbon in a 6.90 L reaction vessel held 2, at 900 K until equilibrium is attained? mass of CS,(g): Question Source: MRG - General Chemistry Publis contact us help about us |privacy policy terms of use careers prime video W
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